Answer: ![\dfrac{2}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B3%7D)
Step-by-step explanation:
When we roll a 6-sided dis , the total possible of outcomes : 1, 2, 3, 4, 5, 6
Thus , the total number of outcomes =6
The favorable outcomes: 2, 1, 3 , 5
Thus , the number of favorable outcomes = 4
Now, the required probability :-
![\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}\\\\=\dfrac{4}{6}=\dfrac{2}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BFavorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B4%7D%7B6%7D%3D%5Cdfrac%7B2%7D%7B3%7D)
Hence, the probability of rolling a 6 sided die and getting a 2 or an odd number![=\dfrac{2}{3}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B2%7D%7B3%7D)