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bixtya [17]
2 years ago
14

What is the value of x that makes the given equation true 9+8x-4-5x=-19

Mathematics
1 answer:
Elena L [17]2 years ago
8 0

Answer:

x = -8

Step-by-step explanation:

9+8x-4-5x=-19

5+8x-5x=-19

5+3x=-19

-5 =-19

3x = -24

3/3 = -24/3

x= -8

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A quadratic equation is shown below:
sweet [91]

Answer:

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( 1.8333, -0.08333)

Part B:

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Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

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6x = 11

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The corresponding y value is determined by substituting x = 11/6 into the original equation;

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y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

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From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
3 years ago
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