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balu736 [363]
3 years ago
9

In the expression 90 5z,the coefficient term is

Mathematics
1 answer:
jekas [21]3 years ago
5 0
The coefficient is the number being multiplied by the variable
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9(14-5)-42 evaluate expression
Ulleksa [173]

Good evening

Answer:

<h2>39</h2><h2 />

Step-by-step explanation:

9(14-5)-42 = 9×9 - 42

                = 81 - 42

                = 39

________________

:)

8 0
3 years ago
What is the standard form when your ordered pairs are (4,5) and your slope is 5/4?
lara31 [8.8K]
The slope (m) and the ordered pairs are given.
In order to arrive at the standard form : AX + BY = C, we need to form the slope-intercept form first : y = mx + b

Substitute the values in order to get the intercept (b)
y = mx + b
5 = 5/4 * 4 + b
5 = 5 + b
b = 0

So given the m = 5/4, b = 0
y = mx + b
y = 5/4x+ 0

Converting it to Standard Form
y = 5/4x + 0
5/4x - y = 0 (multiply both sides by 4)
5x - 4y = 0

<span>So the Standard form is 5x - 4y = 0</span>
3 0
3 years ago
Simplify the problem: Sin theta Sec Theta
kherson [118]

Answer:

\tan \theta

Step-by-step explanation:

We have to simplify the following expression as given by

\sin \theta \times \sec \theta

= \frac{\sin \theta}{\cos \theta}

= \tan \theta ( Answer )

Because, we know that \sec \theta =\frac{1}{\cos \theta} and \tan \theta = \frac{\sin \theta}{\cos \theta}

If we consider \sin \theta = \frac{Perpendicular}{Hypotenuse} and \sec \theta = \frac{Hypotenuse}{Base},

then \sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta

3 0
3 years ago
What does it mean reflection across ×=3
Advocard [28]
You draw a vertical line on the point (3,0) and a vertical like looks like———>>> | , then whatever shape or point it gives you, you reflect off of that line like if it was a mirror
4 0
3 years ago
Read 2 more answers
Choose all of the expressions that are equal to 61. |−61| the opposite of −61 the opposite of 61 the distance from zero to −61 −
igomit [66]

Step-by-step explanation:

We need to choose all the expressions that are equal to 61.

(i) |−61| : It is true. Modulus of any negative number gives positive number. |-61|=61.

(ii) The opposite of −61 ; It is true. Opposite of negative is positive.

(iii) The opposite of 61 : It is false. The opposite of 61 gives -61.

(iv) distance from zero to −61 : It is true. Distance is positive always.

(v) −|61| : False. It remains negative.

(vi) −|−61| : False. It remains negative.

(vii) -(-61) : True. Double negative makes positive .

Hence, the correct options are : (i), (ii), (iv), (vii).

8 0
3 years ago
Read 2 more answers
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