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3 years ago

9

Write in word the following x + 1 > 10

1 answer:

Andrew [12]3 years ago

7 0

x = 10

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Mr. Brown has 14 purple,6 blue, 10 orange face masks. What is the probability that, if selected at random. Mr. Brown will pick o

sattari [20]

Answer:

im pretty sure this is right its a 6/30 chance he would pick blue

Step-by-step explanation:

3 0

3 years ago

Bharat types 20 words/min. How many words can he type in each length of time? a) 5 min b) 30 min c) 23 min

e-lub [12.9K]

Bharat can type words in lengths of time as 100 words, 600 words, and 460 words in 5 minutes, 30 minutes, and 23 minutes respectively.

<h3>What are Arithmetic operations?</h3>

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 12×2 = 24

Bharat types 20 words per minute which are given in the question.

To determine the number of words can he type in each length of time

We have to multiply the time by his typing speed.

The number of words that can be typed by Bharat in 5 minutes :

⇒ 20 × 5

⇒ 100

The number of words that can be typed by Bharat in 30 minutes :

⇒ 20 × 30

⇒ 600

The number of words that can be typed by Bharat in 23 minutes :

⇒ 20 × 23

⇒ 460

Therefore, He can type words in lengths of time as 100 words, 600 words, and 460 words in 5 minutes, 30 minutes, and 23 minutes respectively.

Learn more about Arithmetic operations here:

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3 0

2 years ago

A student number system for a county requires that the student number be 5

Damm [24]

Answer:

B

Step-by-step explanation:

First Character: 21 consonant

2nd 3rd and 4th: 10* 9* 8 = 720

Last Character: 26

Total Ways 21 * 720 * 26 = 393120

6 0

3 years ago

HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$(3.14)(2.5)^{2}(7)$ *Square 2.5*

$(3.14)(6.25)(7)$ *Solve*

≈ $137.375in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(2.5)^{3}$ *Cube 2.5*

$\frac{\frac{4}{3}(3.14)(15.625)}{2}$ *Divide by 2 and Solve*

≈ $32.7083 in^{3}$

Add both volumes

$137.375 + 32.7083$ ≈ $170.083in^{3}$

2.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (3)^{2}(10)$ *Square 3*

$\pi (9)(10)$ *Multiply*

$90\pi$

Sphere:

$V = \frac{4}{3}$ π $r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (3)^{3}$ *Cube 3*

$\frac{4}{3} \pi (27)$ *Multiply*

$36\pi$

Add both Volumes to get total

$90\pi + 36\pi = 126in^{3}$

3.

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(3)^{3}$ *Cube 3*

$\frac{4}{3} (3.14)(27)$ *Multiply*

$113.04m^{3}$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{(3.14)(2)^{2}(5)}{3}$ *Square 2*

$\frac{(3.14)(4)(5)}{3}$ *Solve*

$20.93m^{3}$

Subtract the volumes to get the volume of the blue area

$113.04 - 20.93 = 92.106m^{3}$

4.

Sphere:

$V = \frac{4}{3} \pi r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (8)^{3}$ *Cube 8*

$\\\frac{4}{3}\pi (512)$ *Multiply*

$\\\\\pi (682.6)$ *Solve*

$2133.66in^{3}$ *Divide by 2 since it's a hemisphere*

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (8)^{2}(20)}{3}$ *Square 8*

$\frac{\pi (64)(20)}{3}$ *Multiply and Divide*

$1340.41 in^{3}$

Add both volumes

$1072.33 + 1340.41 = 2412.74in^{3}$

5.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (6)^{2}(16)$ *Square 6*

$\pi (36)(16)$ *Multiply*

$576\pi$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (6)^{2}3}{3}$ *Square 6*

$36\pi$

Add both volumes

$576\pi + 36\pi = 612\pi m^{3}$

Alternative: *Multiply π*

$1922m^{3}$

4 0

3 years ago

Read 2 more answers

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3 years ago