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3 years ago

Njh by how many is 3 fours of 20 greater than 3 fiths of 20?

1 answer:

3 0

To calculate a fraction of a quantity, multiply the quantity by the numerator of the fraction and divide by the denominator

$\frac{3}{4}$ of 20 = (3 × 20 )/4 = $\frac{60}{4}$ = 15

$\frac{3}{5}$ of 20 = (3 × 20 )/5 = $\frac{60}{5}$ = 12

You might be interested in

What is two over twelve + four over nine

noname [10]

Answer:

2/3

Step-by-step explanation:

2/12+4/9

Find a common denominator

16/72+ 32/72

48/72

Simplify

=2/3

Hope this helps

3 0

3 years ago

2 Points

Mashcka [7]

Answer:

C. It would be shifted up.

Step-by-step explanation:

We base it off the y-intercept. Since -7 is less than 1, and our new function has a positive y-intercept, it would indeed be shifted up.

I am joyous to assist you anytime.

5 0

2 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

3 years ago

Read 2 more answers

A publisher reports that 54% of their readers own a particular make of car. A marketing executive wants to test the claim that t

dalvyx [7]

Answer and explanation:

Null hypothesis: p is not 54%

Alternative hypothesis : p is equal 54%

First find standard deviation

Standard deviation is:

σ = √[ P ( 1 - P ) / n ] = √[ 0.54×0.46/220 ] =0.033

The z score is calculated p-P/σ = (0.54-0.50)/0.033 = 1.2121

Therefore we can conclude that proportions are not same and fail to reject the null hypothesis

3 0

3 years ago

A store is having a sale on jelly beans and trail mix. For 6 pounds of jelly beans and 2 pounds of trail mix, the total cost is

Aneli [31]

Answer:

Jelly Bean price per pound = $3.25, Trail Mix price per pound = $1.25

Step-by-step explanation:

Let jb = price per pound of jelly beans

Let tm = price per pound of trail mix

equation 1 -> 6*jb + 2*tm = 22

equation 2 -> 3*jb + 5*tm = 16

simplify equation 1

6*jb + 2tm = 22

2*tm = 22 - 6*jb

divide by 2

tm = 11 - 3*jb

plug this into equation 2

3*jb + 5*tm = 16

3*jb + 5*(11-3*jb) = 16

3*jb + 55 - 15*jb = 16

-12*jb + 55 = 16

-12*jb = 16 - 55

-12*jb = -39

jb = -39/-12

jb = 3.25

then, plug the cost per pound of jelly beans back into the simplified equation 1

tm = 11 - 3*jb

tm = 11 - 3*3.25

tm = 1.25

3 0

2 years ago