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Simora [160]
2 years ago
10

A bag of chocolates is labeled to contain 0.384 pounds of chocolates. The actual weight of the chocolates is 0.3798 pounds. Are

the chocolates heavier or lighter than the weight stated on the label?
Mathematics
1 answer:
Marta_Voda [28]2 years ago
6 0

Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.

Weight:

Using this formula

Chocolate weight=Current weight-Actual weight

Where:

Current weight=0.384

Actual weight=0.3798

Let plug in the formula

Chocolate weight=0.384-0.3798

Chocolate weight=0.0042 ounce

In conclusion, the chocolates stated on the label are 0.0042-ounce lighter.

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Is this the right answer?
iren2701 [21]

Hello from MrBillDoesMath!

Answer:

Yes!


Discussion:

a + b= 2a                =>  subtract "a" from both sides

a - a + b = 2a - a    =>  as (a-a) = 0 and (2a-a) = a

b = a                      (*)

Then  from (*) above

      b-a = b - b       => b-b = 0

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Thank you,

MrB

8 0
3 years ago
Alguien me pude decir una adivinanza o historia q la solución sea una ecuación de segundo grado completa????
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Answer:

Una ecuación de segundo grado completa es algo como:

y = a*x^2 + b*x + c

Un problema tipico que usa ecuaciones de este tipo es algo que nos haga multiplicar dos términos como h*(x + k) y n*(x + j)

Donde h, k, n, y j son números reales.

Entonces planteemos el siguiente caso.

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Acá hay que recordar que para un rectángulo de largo L y ancho W, el área es:

A = L*W

En este caso tendremos:

L = (x + 3cm)

Y el ancho es dos veces eso, entonces:

W = 2*(x + 3cm)

Entonces el area de esta tabla se escribirá como:

A = (x + 3cm)*2*(x + 3cm)

Ahora solo tenemos que expandir eso:

A = 2*x^2 + 12cm*x + 18cm^2

Ahora sabemos que el area de esta tabla es 95cm^2

Entonces:

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0 = 2*x^2 + 12cm*x + (18cm^2 - 95cm^2)

0 = 2*x^2 + 12cm*x - 77 cm^2

Esta es una ecuación de segundo grado completa, la cual deberiamos resolver para encontrar el valor de x como se nos pide en el problema.

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