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3 years ago

ZA and ZB are complementary. If m ZA = (x - 6) º and m2B = (3x) °, find the value of x.

Mathematics

2 answers:

attashe74 [19]3 years ago

8 0

Answer:

x=24

Step-by-step explanation:

If angles are complementary, that means they will add to 90 degrees. We know that ∠A and ∠B are complementary, therefore,

∠A+∠B=90

∠A is equal to x-6, and ∠B is equal to 3x.

x-6+3x=90

Combine like terms (all the terms with variables)

(x+3x)-6=90

4x-6=90

To solve the equation, we want to find out what x is. In order to do this, we have to get x by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.

6 is being subtracted from 4x. The opposite of subtraction is addition, so add 6 to both sides.

4x-6+6=90+6

4x=90+6

4x=96

x is being multiplied by 4. The opposite of multiplication is division, so divide both sides by 4.

4x/4=96/4

x=96/4

x=24

Orlov [11]3 years ago

5 0

Answer:

x = 21°

Step-by-step explanation:

Complementary angles have a sum of 90°. If ∠A + ∠B = 90°, we know that

x - 6° + 3x = 90°.

4x - 6° = 90°

4x = 96°

x = 24°

Hope this helps!

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Step-by-step explanation:

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First, calculate the area of the slate path by subtracting the area of the pond from the area of the larger circle.

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2 years ago

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3 years ago

Solve for “x” -10 = -x^2 + 2x - 6

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4 years ago

Dont leave any links please

Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

$\displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }$

We are given the expression:

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }$

Use the first law of exponent above.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }$

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\$

Multiply m in.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = \frac{ {m}^{2} }{ {n} } }$

Thus the answer is m^2/n.

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3 years ago