Not an actual test question but just curious:
1 answer:
well, when we use the word "the function" we're referring to the dependent part, which depends on the independent, y,x wise, we're referring to the function "y" or f(x) if you wish.
so for an exponential function
is the function ever positive only? it can be
is it negative only? it can be
can it be both? sure thing, most of the time it's both
we can say a function f(x) is always positive when the independent values of "x" yield a positive value only, mind you that when we're talking about "the function" we're really referring to the resulting values in a set, so can the values of the output no matter what "x" we use be always positive? sure, can they also be negative only? sure, how about both? sure thing.
notice the template in the picture below, we can transform any exponential function like the one above 2ˣ with some vertical shift upwards, and is always positive, or -2ˣ with a vertical shift downwards and it's always negative, or we can stretch it about and have -2ˣ shifted upwards so sometimes is positive, and sometimes is negative.
above the x-axis is always positive, below is negative, but with transformations on the parent function it can be any of the three types.
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Answer:
Follows are the solution to the given question:
Step-by-step explanation:
They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.
This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.
if x is between 1 and 365 as well as the occurrence is just all similarly possible
In point i:
That somebody mentions their birthday throughout the party
Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.
In point ii:
Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.
In point iii:
Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.
We are technically FOILing this out... with a power of 3.
(x+y)(x+y)(x+y)
So we can first factor out the first two "x+y"s.
, multiplied by the last "x+y".
Coefficients are the number that comes in front of a variable.
In this case, 1 comes in front of
, 3 comes in front of 
, 3 comes in front of 
, and 1 comes in front of 
.
Thus: 1, 3, 3, 1.
Answer Choice A
(x+y)(x+y)(x+y)
So we can first factor out the first two "x+y"s.
Coefficients are the number that comes in front of a variable.
In this case, 1 comes in front of
Thus: 1, 3, 3, 1.
Answer Choice A