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sergeinik [125]
3 years ago
15

Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

is and replace it in the bag. Then you repeat this process. What is the probability of first selecting a black marble, replacing it and then selecting a red marble?
Mathematics
1 answer:
sweet [91]3 years ago
4 0
(3/5)(2/5)=6/25
.............................
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You are 5 feet tall and cast a 10-foot shadow. a flagpole nearby casts a shadow that is 28 feet. which equation can you use to s
VashaNatasha [74]
As the ratio of your shadow to your height is 2:1 assuming the flagpole would form a similar triangle the shadow is twice the height of the pole meaning the pole is 14 feet tall
3 0
3 years ago
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Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl
GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane n=(-2,-2,1), then r will have the next parametric equations:

x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3

Substitute the value of \lambda in the parametric equations:

x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u

7 0
3 years ago
HELP due tomorrow morning at 7 30 help now please
olga55 [171]
1) 6/15 or 2/5
2) .4 or 40%

for the table its gonna be 14/32 or 7/16
then 5/17 then 11/25 then 8/29 then 3/14
then 9/31 then 12/32 or 3/8 then 8/30 or 4/15 then 2/19 then 15/32
8 0
3 years ago
Plsss help (Cuz i'm dumb:D) Calculate the surface area of the prism below, shape below
marin [14]
Surface area of the the rectangles:
8 * 5 + 8 * 4 + 8 * 3 = 96

Surface area of the two triangles:
Use bh/2 base time height over 2
(4 * 3)/2 = 6
There are 2 triangles, 2 * 6 = 12

12 + 96 = 108
5 0
3 years ago
(1- 7n) • 5 simplify thank you
Bess [88]

Answer:

5-35n

Step-by-step explanation:

5-35n

Just open the parenthesis and multiply by 5.

8 0
2 years ago
Read 2 more answers
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