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2 years ago

The lengths of the sides of triangle ABC are represented in terms of the variable m, where m > 6.

Mathematics

1 answer:

Yanka [14]2 years ago

6 0

Answer:

m(C)<m(B)<m(A).

Step-by-step explanation:

1) according to the condition the shortest side is AB, the longest side is BC, the middle is AC. Then

2) the smallest angle is BCA (or C), the middle angle is ABC (or B), the largest angle is BAC (or A).

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What is the precision of 40 feet

mina [271]

I think it may be the ability to get the correct/same answer (percision) to within 40 feet.

7 0

2 years ago

Hillary buys 3 pounds of Gala apples and some Granny Smith apples. Both kinds of apples cost $4.50 per pound. The total cost is

Elodia [21]

Answer:

24.75 = 3*4.50 + x*4.50

x= 2.5 pounds of Granny Smith apples

Step-by-step explanation:

Gala apples = 3 lbs

Granny apples = x lbs

They cost 4.50 a pound

Total cost = 24.75

Total cost = gala apples * cost per pound + granny apples * cost per pound

Substitute in what we know

24.75 = 3*4.50 + x*4.50

24.75 = 13.50 + 4.5x

Subtract 13.50 from each side

24.75-13.50 = 13.50-13.50 + 4.5x

11.25 = 4.5x

Divide by 4.50 on each side

11.25/4.5 = 4.5x/4.5

2.5 =x

6 0

2 years ago

Read 2 more answers

The sum of four consecutive integers is 174 write and solve an equation that can be used to determine the smallest of the four i

Elan Coil [88]

Answer:

Step-by-step explanation:

Let's say that the smallest is called "a"

We can re-write the question like this:

a+(a+1)+(a+2)+(a+3) = 174

4a+6=174

4a=168

a=42

6 0

3 years ago

Help me out please !!!!!!!!!!!

Bad White [126]

Answer: A=2, B=5, C=4

Step-by-step explanation:

$\frac{6x^{2}+13x-5}{x^{2}-16} \cdot \frac{x+4}{3x-1}\\\frac{(3x-1)(2x+5)}{(x-4)(x+4)} \cdot \frac{x+4}{3x-1}\\\frac{2x+5}{x-4}$

So A=2, B=5, and C=4.

8 0

1 year ago

You are to drive to an interview in another town, at a distance of 270 km on an expressway. The interview is at 11:15 a.m. You p

Yuri [45]

Answer:

the least required speed is 103.88 km/h

Step-by-step explanation:

Data provided in the question:

Total distance = 270 km

Total time to reach = Time between 8 a.m and 11:15 a.m i.e 3.25 hours

Now,

For the distance of 110 km speed was 100 km/h

therefore, the time taken to cover 110 km = $\frac{\textup{Distance}}{\textup{speed}}$

= $\frac{\textup{110 km}}{\textup{100 km/h}}$

= 1.1 hour

For another 43 km speed was 42 km/h

therefore, the time taken to cover 43 km = $\frac{\textup{Distance}}{\textup{speed}}$

= $\frac{\textup{43 km}}{\textup{42 km/h}}$

= 1.0238 hours

Now,

The distance left to be covered = 270 - 110 - 43 = 117 km

Time left = 3.25 h - 1.1 h - 1.0238 h = 1.1262 h

Thus required speed = $\frac{\textup{117 km}}{\textup{1.1262 h}}$

= 103.88 km/h

Hence, the least required speed is 103.88 km/h

6 0

2 years ago