To solve, lets find the volumes of all of the options...
V=l*w*h
A.
6*3*4=72cm³
12*2*3=72cm³
B.
2*4*9=72cm³
9*4*2=72cm³
C.
3*3*8=72cm³
2*6*8=96cm³
D.
6*3*4=72cm³
9*4*3=108cm³
We can conclude that C & D aren't the answer, since they contain prisms that don't have a volume of 72cm³.
Now lets solve for the surface area of A and B...
A.
sA=2(wh+lw+lh)=2(6*3+4*6+4*3)=2(18+24+12)=2(54)=108cm²
sA=2(wh+lw+lh)=2(12*2+3*12+3*2)=2(24+36+6)=2(56)=112cm²
B.
sA=2(wh+lw+lh)=2(2*4+9*2+9*4)=2(8+18+36)=2(62)=124cm²
sA=2(wh+lw+lh)=2(9*4+2*9+2*4)=2(36+18+8)=2(62)=124cm²
A is the only option with both similar volumes of 72cm³ and different surface areas...
Answer=A
So time = distance/speed
515/216 = 2.38 min
in mixed number , 2 whole 83/216 !
80/60 = (80 + 2x)/(60 + 27)
80/60 = (80 + 2x)/87
4/3 = (80 + 2x)/87
3 . (80 + 2x) = 4 . 87
240 + 6x = 348
6x = 348 - 240
6x = 108
x = 18
Answer:
One solution
Step-by-step explanation:
I think its 1 solution but I could be wrong, I looked it up and it said one solution.
