<u>Answer-</u>
<em>The interval where the function is diffrentiable is </em>
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
<u>Solution-</u>
The given expression is,

The function will be differentiable where it is continuous and it will not be differentiable, where the function is not continuous.
The function continuous everywhere except at x = 1, because

at x = 1, its limit does not exist.
Therefore, apart from x=1, this function is differentiable everywhere. The interval will be
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
Answer:
Suppose you have two similar figures , one larger than the other. The scale factor is the ratio of the length of a side of one figure to the length of the corresponding side of the other figure. Here, XYUV=123=4 . So, the scale factor is 4 .Two figures are said to be similar if they are the same shape. In more mathematical language, two figures are similar if their corresponding angles are congruent , and the ratios of the lengths of their corresponding sides are equal. This common ratio is called the scale factor .
Answer:
1,2,5 equal 32
Step-by-step explanation:
In "slope-intercept form"
y = mx +b
the value "m" is called the slope, and the value "b" is called the intercept.
There is another form for the equation of a line, called "point-slope form".
y = m(x -h) +k
where m is still the slope and (h, k) correspond to the (x, y) of the point.
If you write the equation of your line in this "point-slope form", it is easily manipulated to be in the "slope-intercept form".
Fill in
m = (-3/5)
h = -4
k = 0
y = (-3/5)(x -(-4)) +0
Now, you simplify this by using the distributive property.
y = (-3/5)x -(3/5)*4
y = (-3/5)x -12/5 . . . . . . . . . the desired equation
_____
Your understanding of math improves immensely when you become familiar with the terminology. A lot of the rest of it is pattern matching--identifying the parts of one expression that correspond to the parts of another one.
(You will see another version of the "point-slope form", but I find this one the easiest to use for manipulating the equation to other forms.)