Question

I CANT FIGURE THIS OUT I NEED HELP

Answer 1

Answer:

$x\leq 4$

Step-by-step explanation:

Given:

$-\frac{1}{2}x+8\ge 6$

Solve:

$\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}$

$-\frac{1}{2}x+8-8\ge \:6-8$

$\mathrm{Simplify}$

$-\frac{1}{2}x\ge \:-2$

$Multiply\:both\:sides\:by\:-1$

$\left(-\frac{1}{2}x\right)\left(-1\right)\le \left(-2\right)\left(-1\right)$

$\mathrm{Simplify}$

$\frac{1}{2}x\le \:2$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$2\cdot \frac{1}{2}x\le \:2\cdot \:2$

$\mathrm{Simplify}$

$x\leq 4$

$\mathrm{Therefore,}$

$\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:4\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:4]\end{bmatrix}$

~lenvy~