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MAVERICK [17]
3 years ago
7

Christian is going to invest $310 and leave it in an account for 20 years. Assuming the interest is compounded daily, what inter

est rate, to the nearest hundredth of a percent, would be required in order for Christian to end up with $1,000?
Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

r=5.86%

Step-by-step explanation:

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What is the square root of 88 plus(+) the square root of 95?
Tju [1.3M]
Square root of 88 is 9.38083152
Square root of 95 is 9.746794345
9.38083152 + 9.746794345 = 19.12762586

5 0
3 years ago
PQ is parallel to RS. PR and QS are perpendicular to PQ and RS the ratio of the lengths of PR and QS is......
Lady bird [3.3K]

\frac{PQ}{PR} = \frac{RS}{QS} → \frac{PR}{PQ} = \frac{QS}{RS}

the ratio of PR to QS is 1:1 because they are congruent (equal)

If you draw a picture, you will see that PQRS is a parallelogram.


6 0
3 years ago
HG is the perpendicular bisector of FK.<br> What is the length of GH?<br> 8<br> 9<br> 15<br> 34
igor_vitrenko [27]

Answer:

GH=15

Step-by-step explanation:

HK= FK/2= 16/2= 8

Using pythagoras theorem in triangle GHK,

GH²= GK²-HK²

= 17²-8²

= 225

GH= √225

=15

4 0
3 years ago
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
in order to make 5 dozen chocolate chip cookies, I need to use 2 cups of sugar. (a) complete the table, then use the table to dr
sergejj [24]

Answer:

sugar| cookies

(cups) | (dozens)

1        | 2.5

2       | 5

3       | 7.5

4       | 10

Goes up by 2.5 each time

Not sure if this is what you want

Step-by-step explanation:

equation is y = 2.5x

4 0
3 years ago
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