Given:
Consider the below figure attached with this question.
∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°
To find:
The measure of ∠EFH.
Solution:
From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,
Isolate variable terms.
Divide both sides by 13.
The value of x is 4.
Therefore, the measure of ∠EFH is 21°.
Answer:
Option B. 
Step-by-step explanation:
we have
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Complete the square. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
Answer:
Step-by-step explanation:
the curve is representing the projectile. at t=0, the projectile is on the ground. at t=6, the projectile has finished its journey and is back on the ground. In between t=0 and t=6 will be the projectile's peak altitude. the point between t=0 and t=6 is t=3. So plug in t=3 and solve for s(t), and you get 36ft. gg
To find equivalent ratios just factor the same number to both numerator and denominator. I will make the ratios simple by multiplying 2/2 and 3/3 to the originals. To check, set as fraction and cross multiply and you should have the same number. I will show you how to check by doing it to the first ratio.
8:5 16:10 24:15
Check:
8/5 = 16/10
(8)(10)=(5)(16)
80=80
8/5=24/15
(8)(15)=(5)(24)
120=120
4:19 8:38 12:57
6:23 12:46 18:69
Answer:
5 pages
Step-by-step explanation:
10% of 50 is 5
(50 divided by 10 = 5)
