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3 years ago

Find two ratios equivalent to the ratio in exercise 1 8:5 4:19 6:23

Mathematics

1 answer:

Ne4ueva [31]3 years ago

5 0

To find equivalent ratios just factor the same number to both numerator and denominator. I will make the ratios simple by multiplying 2/2 and 3/3 to the originals. To check, set as fraction and cross multiply and you should have the same number. I will show you how to check by doing it to the first ratio.

8:5 16:10 24:15

Check:
8/5 = 16/10
(8)(10)=(5)(16)
80=80

8/5=24/15
(8)(15)=(5)(24)
120=120

4:19 8:38 12:57

6:23 12:46 18:69

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Step-by-step explanation:

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3 years ago

HOOK is a word that has horizontal line symmetry since it is made up of letters that each have horizontal line symmetry. Can you

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Another word that has horizontal line symmetry is "book" and it is possible to form words with vertical line symmetry.

<h3>What is horizontal line symmetry in letters?</h3>

This implies that by dividing the letter in half using a horizontal line both sides would be the same. Lettters with horizontal line symmetry include:

<h3>What are some words with these symmetry?</h3>

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<h3>Are words with vertical line symmetry possible?</h3>

Yes, they are because there are many letters that have this symmetry such as V, T, A, O, M, I, H. For example you can create the words:

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2 years ago

What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir

I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

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dbar ± [TCritical * Sd/√n]

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3 years ago

Plz help me<br> 20 points

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Answer:

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2 years ago

Read 2 more answers

Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two

Damm [24]

Answer:

Step-by-step explanation:

Let S be the set of all graphs having vertex set \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

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3 years ago