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sashaice [31]
2 years ago
9

Determine whether each ordered pair is a solution to the inequality x+y<−1.

Mathematics
1 answer:
polet [3.4K]2 years ago
3 0

Answer:

Choice A.  (10, -1)
Choice B.  (-8, 9)
Choice D.  (6, -3)

Step-by-step explanation:

If we plug the coordinates of point A into the inequality, then we get,
x+y > -2

10 + (-1) > -2
9 > -2
That last inequality is a true statement since 9 is to the right of -2 on the number line. That means (10,-1) is a solution. Choice A is one of the answers.
Choices B and D are also answers
for similar reasons.
Something like choice C is not a solution because
x+y > -2
-1+(-9) > -2
-10 > -2
Which is false.
You should find that choice E is false as well.

If you graphed the inequality and all of the points mentioned (see below), then you can visually confirm the answers. Notice how points A, B and D are in the blue shaded region which is the solution set.
The point E on the boundary does not count as a solution. This is due to the lack of "or equal to" portion of the inequality sign. That visually shows point E is not a solution. Point C isn't a solution either as it's nowhere near the blue shaded region.

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Answer:

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Step-by-step explanation:

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3 years ago
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- 5y – 10x=45<br>- 3y + 10x = -5​
Vsevolod [243]

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Step-by-step explanation:

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- 3y + 10x = -5​

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-8y = 40

y= 40/ -8

y = -5

Substitute y = -5 into any of the equations to get the value of x

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-10x =45 -25

-10× = 20

Divide both sides by -10

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