Luis is proving that the sum of the

Round down this calculation to Ofe ucci piacer ). Order: Uniphyl (theophylline) 5 mg/kg po loading dose stat. The strength of th

Marta_Voda [28]

Answer:

1 tablet

Step-by-step explanation:

Data provided in the question:

The dose of the Uniphyl = 5 mg/kg

Strength of the Uniphyl = 400 mg per tablet

Weight of the patient = 76 kg

Now,

The recommended dose for the patient

= Dose of the Uniphyl × weight of the patient

= 5 mg/kg × 76 kg

= 380 mg

Therefore,

The number of tablets to be administered to the patient

= $\frac{\textup{Recommended dose for the patient}}{\textup{Strength of the Uniphyl}}$

= $\frac{\textup{380}}{\textup{400}}$

= 0.95 ≈ 1 tablet

Hence,

The number of tablets to be administered to the patient is 1

7 0

3 years ago

Sketch the graph by hand using asymptotes and intercepts, but not derivatives. Then use your sketch as a guide to producing grap

Arisa [49]

The local minima of $f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$ are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)

<h3>How to determine the local minima?</h3>

The function is given as:

$f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$

See attachment for the graph of the function f(x)

From the attached graph, we have the following minima:

Minimum = (-1.5, 0)

Minimum = (7.980, 609.174)

The above means that, the local minima are

(x, f(x)) = (-1.5, 0) and (7.980, 609.174)

Read more about graphs at:

brainly.com/question/20394217

#SPJ1

7 0

2 years ago

An urn contain 2 white marbles, 3 green marbles, and 5 red marbles. A marble is drawn and then replaced. Then a second marble is

11111nata11111 [884]

Answer:

1/5

Step-by-step explanation:

To find this you would need to multiply the probability of pulling a white marble to the probability of pulling out a green marble.

1)First you would need the probability of pulling out a white marble. There are 10 marbles in total and out of those 2 are white. So the probability of pulling out a white marble would be 2/10. If you simplify that you would get 1/5 for the probability of pulling out a white marble.

2)Next, you would find the probability of pulling out a green marble. Using the same process that we used to find the probability of pulling out a white marble, we would find the answer to be 3/10. All that we did here was green marbles/total marbles. By filling that in we got 3/10 for the probability of pulling out a green marble.

3)Now all that is left is doing probability of pulling a white marble × probability of pulling out a green marble. This would be 1/5 × 3/10. After solving the answer would be 3/15 which we would simplify down to 1/5 as our final answer.

5 0

3 years ago

Question 1 (1 point)

olga55 [171]

Answer:

1) $2y^{2}+4y-9$

2) $18x^{5}y^{4}z$

3) $6x^{5}-12x^{4}+9x^{3}$

4) 40

5) $x^{3}-7x^{2}+3x+36$

Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

$(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9$

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

$(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z$

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

$-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}$

4) $(4a+5)^{2}$ is a square of a sum, then, by definition you have:

$(a+b)^{2}=a^{2}+2ab+b^{2}$

Then:

$(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25$

The coefficient of the second term is the number in front of the variable a. Then, the answer is: 40

5) Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

$(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36$

6 0

3 years ago

The line segment has an endpoint (5,-6) and the midpoint is (-2,3). Find the other point.

gavmur [86]

Answer:

(-9,12)

Step-by-step explanation:

$Endpoint\:= (5,-6) = x_1,y_1\\Midpoint = \: (-2,3)=x\:,y\\\\x = \frac{x_1+x_2}{2}\\\\ -2 = \frac{5+x_2}{2} \\-4 = 5+x_2\\-4-5=x_2\\-9 =x_2\\\\y = \frac{y_1+y_2}{2} \\\\3 = \frac{-6+y_2}{2} \\6 = -6+y_2\\6+(6)=y_2\\6+6=y_2\\12=y_2\\x_2 ,y_2=(-9,12)$

4 0

3 years ago