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vodomira [7]
2 years ago
6

Which expression is equivalent to the following complex fraction?

Mathematics
1 answer:
svlad2 [7]2 years ago
4 0

Consider the <em>fraction</em> first ;

{:\implies \quad \sf \dfrac{\dfrac{3}{(x-1)}-4}{2-\dfrac{2}{(x-1)}}}

{:\implies \quad \sf \dfrac{\dfrac{3-4(x-1)}{\cancel{(x-1)}}}{\dfrac{2(x-1)-2}{\cancel{(x-1)}}}}

{:\implies \quad \sf \dfrac{3-4x+7}{2(x-1-1)}}

{:\implies \quad \boxed{\bf{\dfrac{-4x+7}{2(x-2)}}}}

<em>Hence, Option B) is </em><em>required</em><em> </em><em>answer</em>

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Please help me with this math question
qwelly [4]
9cm

Imagine there are 2 triangles solve for one 3*3=9\2=4.5

Then add
4.5+4.5=9
7 0
3 years ago
The following are score earned by 15 college students on a 20-point math quiz. (a) calculate the mean, median, and mode scores.
Softa [21]

Answer:

(a) 12.87; 14; 18; (b) median  

Step-by-step explanation:

(a) Statistics

(i) Mean

The mean is the sum of all the data points divided by the number of points.

\begin{array}{rcl}\text{Mean} & = & \dfrac{0 + 2 + 3 + 12 + 12 + 13 + 14 + 14 + 15 + 15 + 18 + 18 + 18 + 19 + 20}{15}\\\\& = & \dfrac{193}{15}\\\\& = & \mathbf{12.87}\\\end{array}

(ii) Median

The median is the middle value in your list of observations.

0, 2, 3, 12, 12, 13, 14, 14, 15, 15, 18, 18, 18, 19, 20

Median = 14

(iii) Mode

The mode is the value that appears most often in your list of observations.

0, 2, 3, 12, 12, 13, 14, 14, 15, 15, 18, 18, 18, 19, 20

Mode = 18

(b) Most representative measure

The mean is dragged down by three low values. The median is the measure that is most representative of the data.

The histogram below shows the distribution of your data.

8 0
3 years ago
4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean
Ede4ka [16]

Adding 2 to each value of the random variable X makes a new random variable X+2. Its mean would be

E[X+2]=E[X]+E[2]=E[X]+2

since expectation is linear, and the expected value of a constant is that constant. E[X] is the mean of X, so the new mean would be

E[X+2]=10+2=12

The variance of a random variable X is

V[X]=E[X^2]-E[X]^2

so the variance of X+2 would be

V[X+2]=E[(X+2)^2]-E[X+2]^2

We already know E[X+2]=12, so simplifying above, we get

V[X+2]=E[X^2+4X+4]-12^2

V[X+2]=E[X^2]+4E[X]+4-12^2

V[X+2]=(V[X]+E[X]^2)+4E[X]-140

Standard deviation is the square root of variance, so V[X]=3^2=9.

\implies V[X+2]=(9+10^2)+4(10)-140=9

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of aX+b for a,b\in\mathbb R is

V[aX+b]=a^2V[X]+b^2V[1]

but the variance of a constant is 0. In this case, a=1, so we're left with V[X+2]=V[X], as expected.

5 0
3 years ago
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Lesechka [4]

Answer:


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What is one more than -49
sasho [114]
It would be -50 I hope this answers your question 

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