One number is seven more than another. If their sum is -3 find the numbers

serious [3.7K]

Y=6x+4
Blanks from left to right:
-14,-2,10,22,6x+4

5 0

2 years ago

A recipe for a batch of 3 dozen chocolate chip cookies calls for 3 cups of flour, one cup of sugar, and 2 cups of chocolate chip

BaLLatris [955]

Answer:

2 cups of flour

2/3 cup of sugar

1 1/3 cups of chocolate chips

Step-by-step explanation:

3 dozen chocolate chip cookies

3 cups of flour

1 cup of sugar

2 cups of chocolate chips

The recipe is for 3 dozen cookies as stated above.

If you make 2 dozen cookies, then you are making 2/3 of the recipe since 2 is 2/3 of 3.

That means you need 2/3 of all the ingredients.

2/3 × 3 dozen chocolate chip cookies

2/3 × 3 cups of flour

2/3 × 1 cup of sugar

2/3 × 2 cups of chocolate chips

We simplify the amounts to:

2 dozen chocolate chip cookies

2 cups of flour

2/3 cup of sugar

1 1/3 cups of chocolate chips

3 0

3 years ago

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 more Small boxes sold than Large boxes.

Step-by-step explanation:

This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable.

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have two equations of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

Given Information:

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were 10 Large Boxes and 20 Small Boxes sold, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0

4 years ago

At a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least o

ycow [4]

Answer:

15%

Step-by-step explanation:

37.5% of the 40% of students who walk have been late, so ...

0.375 · 0.40 = 0.1500 = 15%

of the students in the school both walk and have been late.

The probability that the student selected walks and has been late is 15%.

7 0

3 years ago

Please help me it is due tomorrow i beg of you I will give extra points

Vinil7 [7]

first pic is X and the other is Y just tip on how to do it

4 0

3 years ago