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Goshia [24]
2 years ago
10

If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is

Physics
2 answers:
Anvisha [2.4K]2 years ago
7 0

Question :-

  • If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

  • Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\bigstar \:  \:  \:  \boxed { \sf{ \: Acceleration \:  =  \:  \dfrac{v \:  -  \: u}{t} \:  }} \\

Where ,

  • V denotes to Final Velocity .
  • U denotes to Initial Velocity .
  • T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\dag \:  \:  \:  \:  \sf{Acceleration \:  =  \:  \dfrac{Final  \: Velocity \:  -  \: Initial \: Velocity}{Time} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{0 \:  -  \: 60}{85} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{60}{85} } \\

\longmapsto \:  \:  \: \textbf {\textsf {Acceleration \:  =  \: 0.70 }}

Hence :-

  • Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

  • Kindly Scroll the Screen from Right to Left for Better View .
iogann1982 [59]2 years ago
7 0

Answer:

Question :-

If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}

★

Acceleration=

t

v−u

Where ,

V denotes to Final Velocity .

U denotes to Initial Velocity .

T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}

†Acceleration=

Time

FinalVelocity−InitialVelocity

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}

⟼Acceleration=

85

0−60

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}

⟼Acceleration=

85

60

\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70

Hence :-

Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

Kindly Scroll the Screen from Right to Left for Better View .

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