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seropon [69]
2 years ago
13

I need this asap give me the right answer

Mathematics
1 answer:
anastassius [24]2 years ago
3 0

Answer:

Its 320 i think its so many numbers my eyes cant keep up

Step-by-step explanation:

just add em all up

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Simplify the expression write the expression in scientific notation (5 times 10^7) (6 times 10^4)
Crank

5 times 10^7= 50000000

6 times 10^4= 60000

<span>(50000000)</span><span>(60000)</span>

<u>Answer</u>
3000000000000
8 0
3 years ago
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Mark can make 9 pancakes in 15 minutes, and Charlotte can make 42 pancakes in 45 minutes. Working together, how many minutes wou
Sedbober [7]

Answer:

60 mins

Step-by-step explanation:

15+45=60

4 0
3 years ago
Pls help test due soon!
andreev551 [17]
3 years
15 = 250(0.06)
45/15 = 3
4 0
3 years ago
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What is the solution to this system of equations?
laiz [17]

Answer:

Step-by-step explanation:

Solving by elimination and substitution:

x + y = 7

x − y = − 3

on adding the two equations  

y  gets cancelled

x + y = 7

x − y = − 3

2 x = 4

x = 4 2 = 2

substituting this value of x  

in equation 1:

x +y = 7

2 + y = 7

y = 7 − 2

y = 5

the solution for the system of equations are :

x = 2

y = 5

Hope it helps pls mark as brainliest

4 0
3 years ago
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How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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