5 times 10^7= 50000000
6 times 10^4= 60000
<span>(50000000)</span><span>(60000)</span>
<u>Answer</u>
3000000000000
3 years
15 = 250(0.06)
45/15 = 3
Answer:
Step-by-step explanation:
Solving by elimination and substitution:
x
+
y
=
7
x
−
y
=
−
3
on adding the two equations
y gets cancelled
x
+
y
=
7
x
−
y
=
−
3
2
x
=
4
x
=
4
2
=
2
substituting this value of x
in equation 1:
x
+y
=
7
2
+
y
=
7
y
=
7
−
2
y
=
5
the solution for the system of equations are :
x
=
2
y
=
5
Hope it helps pls mark as brainliest
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru