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Natasha2012 [34]
3 years ago
15

Find the coterminal angle between 0 and 360°of the angle -280°

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer: So, the coterminal angle of 450° is -90°.

Step-by-step explanation:(i) 395°  

Write 395° in terms of 360°.

395°  =  360° + 35°

So, the coterminal angle of 395° is 35◦

(ii) 525°

Write 525° in terms of 360°.

525°  =  360° + 165°  

So, the coterminal angle of 525° is 165°.

(iii) 1150°

Write 1150° in terms of 360°.

1150°  =  3(360°) + 70°  

So, the coterminal angle of 1150° is 70°.

(iv) -270°

Write -270° in terms of 360°.

-270°  =  -360° + 90°

So, the coterminal angle of 270° is 90°.

(v) -450°

Write -450° in terms of 360°.

-450°  =  -360° - 90°  

So, the coterminal angle of 450° is -90°.

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Answer:

it means positive 5. because negative + negative = positive or you can think like -1 times -5 which is 5.

Step-by-step explanation:

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3 years ago
The room numbers of two adjacent classrooms are two consecutive even integers. If their sum is 654, find the classroom numbers.
IRINA_888 [86]

Answer: It is 326 and 328.


Step-by-step explanation: We know that the numbers must be even and consecutive, so we can figure this problem out by trial and error. Divide 654 by two, and then keep going until you get the proper answer.

(Hope this helps :) )


4 0
2 years ago
48+(2*13)/110= ?<br> A) .673<br> B) .7214<br> C) 51.5<br> D) 35.62
siniylev [52]
48 + (2*13) / 110
PE(MD)(AS)

2 * 13 = 26
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Sakima Lena is employed at a restaurant. He has family medical coverage through the company’s group medical plan. The annual cos
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3 years ago
Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.
ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

a_n = a_1 + d(n-1)

Plug in a_1 = 4, \ d = 8, \ n = 10 and you should get the following:

a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\

The tenth term is <u>76</u>

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}

---------

In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in a_n = a_1 + d(n-1) which shifts everything one spot to the left.

7 0
2 years ago
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