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Alexxandr [17]
2 years ago
15

What is the measure of an angle that turns through 1/5 of a circe

Mathematics
1 answer:
Ede4ka [16]2 years ago
7 0
5 is the answer excuse it converts back to 5
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Please help me solve these.
ale4655 [162]
Oh gosh i wish i knew how to do that what grade are u in cause i remember having that last year but dont remember.
5 0
3 years ago
On a given planet, the weight of an object varies directly with the mass of the object. Suppose that an object whose mass is 9 k
nadya68 [22]

Answer:

6 kg

Step-by-step explanation:

Given is weight of an object directly varies with the mass of the object .

Let the constant of proportionality be k

So,

Weight = K×(mass of the object)

For an object , weight = 45 N

                        mass = 9 kg

So , 45 = K×9

      K = 5.

Now, for the other object ,

Weight = 30 N. K = 5 (as obtained above)

So, 30 = 5×(mass of the object)

mass of the object = 6 kg.

5 0
4 years ago
Draw segment EF so that is bisects RS. Mark their intersection appoint A
Neko [114]

Step-by-step explanation:

EF is a segment so it's a line with the end points as E and F. Line RS bisects(cuts in half) line EF. Then where the two lines meet is where A is.

Hope this helped.

4 0
3 years ago
The polynomial 3x2 is a with a degree of .
ZanzabumX [31]

To determine the degree of a polynomial, you look at every term:

  • if the term involves only one variable, the degree of that term is the exponent of the variable
  • if the term involves more than one variable, the degree of that term is the sum of the exponents of the variables.

So, for example, the degree of 7x^{55} is 55, while the degree of xy^2z^4 is 1+2+4 = 7

Finally, the term of the degree of the polynomial is the highest degree among its terms.

So, 3x^2 is a degree 2 polynomial (although it only has one term)

similarly, x^2y + 3xy^2 + 1 is a degree 3 polynomial: the first two terms have degree 3, because they have exponents 2 and 1.

6 0
3 years ago
Read 2 more answers
Fifteen years ago, you deposited $12,500 into an investment fund. Five years ago, you added an
True [87]

Answer:

a) 8.16%

b) $65,762.50

c) $39,701.07

Step-by-step explanation:

Given:

15 years ago, Initial investment = $12500

5 years ago, Investment = $20000

Nominal interest = 8% semi annually for first 10 years

Interest2= 6.5% compunded annually for last five years

a) for the effective annual interest rate (EAR) in the first 10 years, let's use the formula:

[1+(nominal interest rate/number of compounding periods)]^ number of compounding periods-1

EAR = [1 + (\frac{0.08}{2})]^2 - 1

= (1 + 0.04)^2 - 1

= (1.04)^2 - 1

= 1.0816 - 1

= 0.0816

= 8.16%

The effective annual interesting rate, EAR = 8.16 %

b) To find the amount in my account today.

Let's first find the amount for $12500 for 10 years compounded semi annually

= 12,500 +( 12,500 * 8.160% * 10)

= $ 22,700

Let's also find the amount for $32,500($12,500+$20,000) for 5 Years compoundeed annually

$32,500 + ($32,500 * 6.5% *5)

= $ 43,062.50

Money in account today will be:

$22,700 + $43,062.50

= $65,762.50

c) Let's the amount I should have invested to be X

For first 10 years at 8.160%, we have:

Interest Amount = ( X * 8.160% * 10 ) = 0.8160 X

For next 5 years at 6.5%, we have:

Interest Amount = (X * 6.5% * 5) = 0.325 X

Therefore the total money at the end of 15 Years = 85000

0.8160X + 0.3250X + X = $85,000

= 2.141X = $85,000

X = 85,000/2.141

X = 39,701.074 ≈ $39,700

If I wish to have $85,000 now, I should have invested $39,700 15 years ago

7 0
3 years ago
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