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algol [13]
3 years ago
9

A rectangular yard measures 12 feet by 10 feet. Find the cost of installing a fence around the yard if the fence costs

Mathematics
1 answer:
rewona [7]3 years ago
3 0

Answer:

$372

Step-by-step explanation:

12 × 10 = 120

1 foot = $3.10

120 feet = ?

120 feet × $3.10

= $372

$372÷ 1 foot = $372

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Can someone help with math?
algol [13]

Answer:

A. {4,3}

Step-by-step explanation:

x -2y = -2

    y = - 3x +15

x - 2(-3x+15) = -2

x +6x - 30 = -2

7x = 28

x = 4

y = - 3x +15 = - 3*4 + 15 = -12 + 15 = 3

{4,3}

5 0
3 years ago
Part A: Virginia earned $14 walking her neighbors' dogs on Saturday. She earned some extra money on Sunday doing the same thing.
shutvik [7]
Part A: 14 + 14 = y or 14•2 = y
Part B: (n•2) - 2 = a

Not 100% sure that this is correct but, hope this helps! :) If you have any questions than ask me.
7 0
3 years ago
The Brown family needs to rent a truck for their upcoming move. Express Movers will charge them $25 for the first day and $0.80
ankoles [38]
Express Movers equation would be y= 25 + .8x
Smith equation would be y= 35 + .6x
if you went 14 miles with Movers, you would go 1 mile with Smith for the same price.
8 0
3 years ago
Ben spent 1/6 of his money on a burger, fries, and a drink. Then he spent half of the money he had left: $5 on a magazine, $8.25
Ket [755]

The amount of money Ben had to begin with after spending 1/6 and 1/2 of it is 57 dollars.

<h3>How to find the how much money he had with an equation?</h3>

let

x = amount he had to begin with

He  spent 1/6 of his money on a burger, fries, and a drink. Therefore,

amount spent on burger, fries, and a drink = 1  / 6 x

Hence,

amount he had left = x - 1 / 6 x =6x - x /6 = 5 / 6 x

Then he spent half of the money he had left.

1  / 2(5  /6 x) = 5 + 8.25 + 10.50

5 / 12 x = 23.75

cross multiply

5x = 23.75 × 12

5x = 285

divide both sides by 5

x = 285 / 5

x = 57

Therefore, the amount of money he have to begin with is $57.

learn more on equation here: brainly.com/question/5718696

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
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