Create an algebraic expression that always results in 6 more than a multiple of 5 if the variable is an integer. no links
2 answers:
<h3>Hello!</h3>
Let's create an expression that always results in 6 more than a multiple of 5.
First, let the unknown number be x.
Then, we should multiply it times 5 and add 6 (6 more means we add 6)
So the expression is
5x+6
Will this work? We can easily check by plugging in some numbers:
5(2)+6
10+6
10 is a multiple of 5
16 ✓
Try another number:
5(3)+6
15+6
21 ✓
Try a negative number:
5(-3)+6
-15+6
-9 ✓
Try zero:
5(0)+6
0+6
6 ✓
<h3>Notes:</h3>
- Hope everything is clear.
- Let me know if you have any questions!
- Enjoy your day!
<h3>Answered by</h3>
Answer:
<u>5x + 6</u>
Step-by-step explanation:
<u>To Do</u>
- Creating an algebraic expression that always results in 6 more than a multiple of 5 if the variable is an integer
<u />
<u>Solution</u>
- Let the variable be x
- Multiple of 5 ⇒ 5x
- 6 more ⇒ +6
- Expression ⇒ <u>5x + 6</u>
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A = πr² + πrl
306.00 = 3.14(6)² + 3.14(6)(l)
306.00 = 3.14(36) + 3.14(6l)
306.00 = 113.04 + 18.84l
- 113.04 - 113.04
192.96 = 18.84l
18.84 18.84
10.24 ≈ l
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It is 16 have a noice day :)
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