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Lady_Fox [76]
2 years ago
9

Create an algebraic expression that always results in 6 more than a multiple of 5 if the variable is an integer. no links

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
7 0
<h3>Hello!</h3>

===========================================

Let's create an expression that always results in 6 more than a multiple of 5.

First, let the unknown number be x.

Then, we should multiply it times 5 and add 6 (6 more means we add 6)

So the expression is

5x+6

Will this work? We can easily check by plugging in some numbers:

5(2)+6

10+6

10 is a multiple of 5

16 ✓

Try another number:

5(3)+6

15+6

21 ✓

Try a negative number:

5(-3)+6

-15+6

-9 ✓

Try zero:

5(0)+6

0+6

6 ✓

============================

<h3>Notes:</h3>
  • Hope everything is clear.
  • Let me know if you have any questions!
  • Enjoy your day!
<h3>Answered by</h3>

^\square\boxed{An~Emotional~Helper}^\square^\bigstar

Sergio [31]2 years ago
6 0

Answer:

<u>5x + 6</u>

Step-by-step explanation:

<u>To Do</u>

  • Creating an algebraic expression that always results in 6 more than a multiple of 5 if the variable is an integer

<u />

<u>Solution</u>

  • Let the variable be x
  • Multiple of 5 ⇒ 5x
  • 6 more ⇒ +6
  • Expression ⇒ <u>5x + 6</u>
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qwelly [4]

Answer:

x = 58°

Step-by-step explanation:

ABCD is a cyclic quadrilateral and opposite angles are supplementary , so

∠ DAB = 180° - 121° = 59°

The angle between a tangent and a chord is equal to the angle in the alternate segment, then

∠ ABD = 63° , thus

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5 0
3 years ago
-4x + 64 &lt; 242 + 3x<br> Giving extra points
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Answer:

x>−178/7

Step-by-step explanation:

I'm assuming you wanted to solve for the inequality of x, if so this is the answer.

6 0
3 years ago
At a small midwestern college:
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3 years ago
On the basis of the graph, answers the following questions.
Pepsi [2]

a) The factors have the form:

(x-x_1)

where x1 is a zero of the function. A zero is a point at which the graph intercepts the x-axis. From the graph, the zeros are:

-6, -4, 2, and 3

Therefore, the factors are:

(x + 6)

(x + 4)

(x - 2)

(x - 3)

b) Multiplying all these factors we get a polynomial, p(x), with the zeros of the graph. That is:

p(x) = (x + 6)(x + 4)(x - 2)(x - 3)

c) Yes, it is possible to find other polynomials with the same zeros. To do that we have to multiply p(x) by a constant. For example, multiplying by 2:

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and f(x) has the same zeros as p(x)

d) Every polynomial obtained in the previous way, multiplying p(x) by a constant, will have a different graph. In conclusion, it is not possible to find other polynomials with the same zeros and the same graph.

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vredina [299]
Hi there!

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Since 2/9x + y = 2 is in standard form, it'd be the answer. 

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3 0
3 years ago
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