What percent is 14 of 70

Point Q' is the image of Q(-7, -6) under the translation (x, y) + (x + 12, y + 8).

Lina20 [59]

Answer:

The co-ordinates of Q' is (5,2).

Step-by-step explanation:

Given:

Pre-image point

Q(-7,-6)

To find Image point Q' after following translation.

$(x,y)\rightarrow (x+12,y+8)$

Solution:

Translation rules:

Horizontal shift:

$(x,y)\rightarrow (x+k,y)$

when $K>0$ the point is translated $k$ units to the right.

when $K$ the point is translated $k$ units to the left.

Vertical shift:

$(x,y)\rightarrow (x,y+k)$

when $K>0$ the point is translated $k$ units up.

when $K$ the point is translated $k$ units down.

Given translation $(x,y)\rightarrow (x+12,y+8)$ shows the point is shifted 12 units to the right and 8 units up.

The point Q' can be given as:

Q'= $(-7+12,-6+8)=(5,2)$

So, the co-ordinates of Q' is (5,2). (Answer)

7 0

3 years ago

(951² - 159²)÷(7539²-357²) x (258²-852²)

Marysya12 [62]

Answer:

(879,120)÷(56709072) ×(-659340)=-10221.274

Step-by-step explanation:

we use bedmas rules when it comes to long solving questions.

5 0

2 years ago

Can someone pls show how to do this is with explanation

Keith_Richards [23]

1m = 100 cm
0.05 m = 5cm
1 km = 10000 cm
0.00005 km = 5 cm
Yes they are equal

(Mark me the brainliest if this has helped!)

4 0

2 years ago

Flying against the wind, an airplane travels 7520 kilometers in 8 hours. Flying with the wind, the same plane travels 6500 kilom

bezimeni [28]

Answer:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

Step-by-step explanation:

Let the rate (speed) of the plane in still air = u km/h

Let the rate (speed) of the wind = v km/h

Formula for speed is:

$Speed = \dfrac{Distance}{Time}$

Given that against the wind, airplane travels 7520 km in 8 hours.

The speed against the wind will be slower so,

Against the wind, speed = (u -v ) km/h

Using above formula:

$(u-v) = \dfrac{7520}{8} km/h\\(u-v) = 940 km/h ..... (1)$

Given that with the wind, airplane travels 6500 km in 5 hours.

The speed with the wind will be faster so,

With the wind, speed = (u +v ) km/h

Using above formula:

$(u+v) = \dfrac{6520}{5} km/h\\(u+v) = 1300 km/h ..... (2)$

Adding (1) and (2) to solve for u and v:

$2u = 2240\\\Rightarrow u = 1120\ km/h$

Putting u in (1):

$1120-u=940\\\Rightarrow u = 180\ km/h$

So, the answers are:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

6 0

2 years ago

Solve the following system of equations by the substitution method.

ruslelena [56]

5x = y + 6 (I)
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 → $x = \frac{y+6}{5}$

Soon:
2x - 3y = 4 → $2* (\frac{y+6}{5}) - 3y = 4\to \frac{2y+12}{5} - 3y = 4$
least common multiple (5)
 $\frac{2y+12}{5} - 3y = 4\to \frac{2y+12}{\diagup\!\!\!\!\!5} - \frac{15y}{\diagup\!\!\!\!\!5} = \frac{20}{\diagup\!\!\!\!\!5}$
$2y + 12 - 15y = 20$
$- 15y + 2y = 20 - 12$
$- 13y = 8$
$\boxed{\boxed{y = - \frac{8}{13} }}\end{array}}\qquad\quad\checkmark$

4 0

3 years ago