Answer:
H0 : μ = 91000
H1 : μ ≠ 91000
Test statistic = - 2.594
Pvalue = 0.016
|Tcritical | = 2.064
Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.
Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.
Step-by-step explanation:
The hypothesis :
H0 : μ = 91000
H1 : μ ≠ 91000
From the data given :
77600 76000 90700 97200 90700
101800 78700 81300 84200 97600
77500 75700 89400 84300 78700
84600 87700 103400 83800 101300
94700 69200 95400 61500 68800
Using calculator :
Sample mean, xbar = 85272
Sample standard deviation, s = 11039.23
Sample size, n = 25
The test statistic :
(xbar - μ) ÷ (s/√(n))
(85272 - 91000) / (11039.23/√(25)
Test statistic = - 5728 / 2207.846
Test statistic = - 2.594
The Pvalue : df = n - 1 = 25 - 1 = 24
Pvalue(-2.594, 24) = 0.0159
Decision region :
Reject H0 ; If Pvalue < α ;
α = 0.05
Using the critical value :
Decision region :
Reject H0 ; If Test statistic > |Tcritical;
Tcritical value at df = 24 ; α = 0.05 ;
|Tcritical | = 2.064
Hence,
We Reject H0 ; Since, |Test statistic| > |Tcritical|and conclude that mean salary depends differs
