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Basile [38]
3 years ago
10

The sum of the digits of a two-digit number is 7 .When the digits are interchanged the reversed number is five times the tens di

git of the original number find the original number .
frnds pls help me

I want answer with full process pls help me​
pls frnds do it fast pls help me
Mathematics
1 answer:
Yanka [14]3 years ago
5 0

Answer:

Original number is 52.

Step-by-step explanation:

1) Two digit number xy,

it can be written as 10x + y.

2) The sum of the digits of a two-digit number is 7.

x + y = 7

3) The digits are interchanged the reversed number is yx,

the new number can be written as 10y + x.

4)  The original number is 10x + y, so the tens digit of the original number  is x.

5) Five times the tens digit of the original number is 5*x.

6) The reversed number is five times the tens digit of the original number:

10y + x = 5*x

7) We have system of two equations

x + y = 7  ---->  x = 7 - y

10y + x = 5*x --->   10y - 4x = 0

10y - 4x = 0

10y - 4(7 - y) =0

10y - 28 + 4y = 0

14y = 28

y = 2

x = 7 - y = 7 - 2 = 5

x = 5

Original number is 52.

New number 25.

Check:

Original number is 52, the tens digit is 5.

The reversed number (25) is five times the tens digit of the original number find the original number .

25 = 5*5 True

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If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?
Keith_Richards [23]

Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

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Using (i)

BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7

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3 0
3 years ago
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mars1129 [50]
Difference between 25 and 35 = 35 -25
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Then
percentage by which 25 is less than 35 =(10/35) * 100
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So 25 is 28.57% less than 35.This is the only clear way of solving these kind of problems. I hope you have understood the method used to solve this problem. Hopefully you can do such type of problems without needing any help.
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---------------------------------------------------------------------------------------------------------

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