The name of the user defined function is: footballMatch
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
Answer:
# include <conio.h>
#include <iostream.h>
using namespace std;
main()
{
int billamount[12];
char monthname["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
<em>for (int month = 1 ; month<=12; month++)</em>
<em>{</em>
<em>cout<<"Enter the amount of bill for the month"<<month;</em>
<em>cin>>billamount[month];</em>
<em>}</em>
for (i=0; i<= 12; i++)
{
if (billamount[0]<billamount[i])
billamount[0]=billamount[i];
monthname[0]=monthname[i];
}
<em>cout<<"Maximum months phone bill"<<monthname[0]<<"="<<billamount[0]</em>
<em />
getch();
}
The CC field is used to send a copy of an email. CC stands for carbon copy.
Answer:
The answer to this question is the option "A".
Explanation:
In this question, the answer is option "A" which is the library. The term library stands in programming language for library made available across implementations of a programming language. In the programming section library is a collection of pre-compiled modules that a program can use and modules are stored in object format. We can reuse these modules in our program. So the answer to this question is the library.
