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inysia [295]
3 years ago
7

Which of the following is not a bus type A. Address bus B. Data bus C. Memory bus D. Control bus ​

Computers and Technology
2 answers:
SVEN [57.7K]3 years ago
8 0

Answer:

Answer is memory bus.

Explanation:

Answer is memory bus.

Finger [1]3 years ago
6 0

Answer:

The answer is C (Memory bus)

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Write a program that displays the values in the list numbers in ascendingorder sorted by the sum of their digits.
melisa1 [442]

Answer:

Here is the Python program.

def DigitList(number):  

   return sum(map(int, str(number)))  

 

list = [18, 23, 35, 43, 51]  

ascendList = sorted(list, key = DigitList)  

print(ascendList)

Explanation:

The method DigitList() takes value of numbers of the list as parameter. So this parameter is basically the element of the list. return sum(map(int, str(number)))  statement in the DigitList() method consists of three methods i.e. str(), map() and sum(). First the str() method converts each element of the list to string. Then the map() function is used which converts every element of list to another list. That list will now contain digits as its elements. In short each number is converted to the string by str() and then the digit characters of each string number is mapped to integers. Now these digits are passed to sum() function which returns the sum. For example we have two numbers 12 and 31 in the list so each digit is 1 2 and 3 1 are added to get the sum 3 and 4. So now the list would have 3 4 as elements.

Now list = [18, 23, 35, 43, 51] is a list of 5 numbers. ascendList = sorted(list, key = DigitList)  statement has a sorted() method which takes two arguments i.e. the above list and a key which is equal to the DigitList which means that the list is sorted out using key=DigitList. DigitList simply converts each number of list to a another list with its digits as elements and then returns the sum of the digits. Now using DigitList method as key the element of the list = [18, 23, 35, 43, 51] are sorted using sorted() method. print(ascendList) statement prints the resultant list with values in the list in ascending order sorted by the sum of their digits.

So for the above list [18, 23, 35, 43, 51] the sum of each number is 9 ,5, 8, 7, 6 and then list is sorted according to the sum values in ascending order. So 5 is the smallest, then comes 6, 7, 8 and 9. So 5 is the sum of the number 23, 6 is the sum of 51, 7 is the sum of 43, 8 is the sum of 35 and 9 is the sum of 18. So now after sorting these numbers according to their sum the output list is:

[23, 51, 43, 35, 18]                                                                                                          

4 0
3 years ago
Please help ⊙﹏⊙ thank you <3
mr_godi [17]

Answer:1. the importance of preventing maintenance is to advoid injuries or harm

2.true

Explanation:

5 0
3 years ago
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Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a
kkurt [141]

Answer:

(a) Calculate the average CPI for each machine, M1, and M2

Average CPI = Cycles per Instruction * Frequency of each  Instruction

                     = CPI * F

For Machine M1:

Cycles per Instruction/ Clocks per Instruction =  (60%)* 1 + (30%)*2 + (10%)*4

                                                                        = (0.60) * 1 + (0.30) * 2 + (0.10) * 4

                                                                          = 0.6 + 0.6 + 0.4

                                                                          = 1.6

For Machine M2:

Cycles per Instruction/ Clocks per Instruction=  (60%)*2 + (30%)*3 + (10%)*4

                                                                         = (0.60) *2 + (0.30) * 3 + (0.10) *4        

                                                                         = 1.2 + 0.9 + 0.4

                                                                          = 2.5

(b) Calculate the average MIPS ratings for each machine, M1 and M2.

MIPS rating can be found by using this formula

MIPS rating = Instruction Count / Execution Time * 10^6

                   = Instruction count  / IC X CPI * Clock cycle time * 10^6

                   = IC X Clock rate  / IC X CPI X 10^6

                   = Clock Rate/(CPI * 10^6)

MIPS rating for Machine M1:

The clock rate for M1 is 80 MHz and CPI calculated in (a) is 1.6 So:

MIPS rating = (80 * 10^6) / (1.6 * 10^6 )

                   =  80000000/ 1600000

                   =  50

MIPS rating for Machine M2:

The clock rate for M1 is 100 MHz and CPI calculated in (a) is 2.5 So:

MIPS rating = (100 * 10^6 ) / (2.5 * 10^6 )

                   =  100000000 / 2500000

                  =  40

(c) Which machine has a smaller MIPS rating?

  • M2 has a smaller MIPS rating which is 40.

Which individual instruction class CPI do you need to change, and by how much, to have this machine have the same or better performance as the machine with the higher MIPS rating.

Machine M1 has the higher MIPS rating than M2 and in order to make M2 perform better than M1, the CPI of instruction class A should be modified. Lets change the instruction class A CPI to 1 in place of 2.

Then:

Cycles per Instruction/ Clocks per Instruction= (60%)*1 + (30%)*3 + (10%)*4

                                                                       = (0.60 * 1) + (0.30 * 3) + (0.10 * 4)

                                                                       = 0.60 + 0.9 + 0.4

                                                                       = 1.9

Average MIPS rating = (100 * 10^6) / (1.9 * 10^6 )

                                   = 100000000 / 1900000

                                   =  52.6

Average MIPS rating is of M2 after changing instruction class A CPI is 52.6 which is better than the average MIPS rating of M1 which is 50.0

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3 years ago
A good place to get hints about how to answer a response question could be a. Your teacher c. Both of these b. The rest of the t
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Pavel [41]

If it help her sleep than yes! Sleep helps you to stay focused during a test.

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