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podryga [215]
3 years ago
15

100 POINTS! ANSWER HAS TO BE CORRECT TO GET BRAINLIEST! HELP!

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

<h2>∠Q corresponds with ∠Z</h2>

Step-by-step explanation:

  1. form a graph
  2. draw  Δ ZNM and ΔPQR on either side of the y- axis
  3. You reflect ΔZMN across the y- axis
  4. Then you translate said triangle up the graph
  5. The corresponding ∠'s will match and overlap.
  6. m∠Q ≅ m∠Z as well as being a corresponding triangle

<h3>Brainliest please?</h3>
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How many solutions does this equation have,3(x-2)+7x=1/2(6x-2)
Alchen [17]

Answer:

x=5/7

Step-by-step explanation:

3(x-2)+7x=1/2(6x-2)

3x-6+7x=3x-1

10x-6=3x-1

10x-3x=-1+6

7x=5

x=5/7

7 0
3 years ago
Read 2 more answers
He scored 3 goals at Saturdays gams and scored 5 goals in yesterdays game . What is his percent of increase?
trasher [3.6K]

Answer: his percent of increase = 66.66%

Step-by-step explanation:

percent of increase = Increase/ Previous goal x 100

Previous goal = 3 goals

Yesterday's goal = 5 goals

Percent of increase = (5-3) / 3 x 100

=2/3 x 100

=0.6666 x 100

=66.66%

5 0
3 years ago
Wrote an expression gor <br> m &lt; RST
grigory [225]

The expression for the angle m∠RST from the given bisctor is; 6x - 18

<h3>How to find the expression for a given angle?</h3>

From the given image in the attachment we are given that;

SQ bisects ∠TSR

m ∠RSQ = 3x - 9

Now, since  SQ is a bisector of ∠TSR, we can say that

m∠RST = 2 * m∠RSQ

Thus angle RST is expressed as;

m∠RST = 2(3x - 9)

m∠RST = 6x - 18

Read more about Angle expression at; brainly.com/question/16953095

#SPJ1

4 0
2 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
blagie [28]

Answer:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

4 0
4 years ago
Please help on this I’m too dum
bezimeni [28]
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.





7 0
4 years ago
Read 2 more answers
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