<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-36%5Cfrax%2B5%2F%28x%2B6%29" id="TexFormula1" title="x^{2} -36\frax+5/(x+6)" al

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Ber [7]

2 years ago

t="x^{2} -36\frax+5/(x+6)" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

6 0

the answer is

x^{2}-31x+5b

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How many quarts of paint if wall is 10 feet long and 8 feet tall and want to cover 50 square feet?

finlep [7]

300 quarts i think
ok

4 0

3 years ago

What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

11111nata11111 [884]

Answer:

$R' = (-1,-0.5)$

Step-by-step explanation:

See attachment for complete question.

From the attachment:

$P = (-3,-3)$

$R = (1,2)$

Dilation:

$D_{(0.5,P)}$

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

$R = (1-(-3),2-(-3))$

$R = (1+3,2+3)$

$R = (4,5)$

Next, apply dilation factor 0.5

$R' = R * 0.5$

$R' = (4,5) * 0.5$

$R' = (4* 0.5,5* 0.5)$

$R' = (2,2.5)$

Lastly, measure R' from the origin by adding the coordinates of P to R'

$R' = (2+(-3),2.5+(-3))$

$R' = (2-3,2.5-3)$

$R' = (-1,-0.5)$

6 0

2 years ago

In 1990, the population of Boston, Massachusetts was 574,283. In 2000, the population was 589,141. What is the percent of change

MrMuchimi

Answer:

Percent of change in population is $2.6$ %

Step-by-step explanation:

Given population of Boston is $574,283$ measured in year $1990$ .

And population of Boston in year $2000$ is $589,141$ .

We need to find percent of change in population.

So, percent change $=\frac{New\ population-Old\ population}{Old\ population}\times100$ %

Here old population is $574,283$ and new population is $589,141$

Plugging these value in formula we get,

Percent change $=\frac{589,141-574,283}{574,283}\times100\\\\=\frac{14858}{574,283}\times100=0.0258\times100\\\\=2.587$

Rounding to nearest tenth 2.6%

8 0

3 years ago

What is the theoretical probability that a coin toss results in two heads showing?

myrzilka [38]

Answer:

Very likely

Step-by-step explanation:

(1/2)x2=1

8 0

3 years ago

How do you write 2x^3 + 2x^2 - 3 as a trinomial?

NARA [144]

Answer: =

6x^2−5x−6

Step-by-step explanation: Multiply each term in one expression times each term in the other, then simplify by combining like terms.

Here are the like terms : =(3x+2)(2x−3)=3x(2x+3x(−3)+2(2x)+2(−3)

= 6x^2−9x+4x−6

=6x2−5x−6

7 0

3 years ago