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vfiekz [6]
3 years ago
12

a segment has and endpoint at (-6, 8). The midpoint is at (-6, 2). What are the coordinates of the other endpoint?

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

(-6,-4)

Step-by-step explanation:

The first endpoint of the line is (-6,8), we can call

x_1 = -6

and

y_1 = 8

Let the last endpoint have coordinates (x_2,y_2)

Also, the midpoint formula is:

(x_1+x_2)/2 , (y_1+y_2)/2

Now, plugging these values is the formula, we get:

(-6+x_2)/2 = -6

-6+x_2=-12

x_2=-12+6 = -6

x_2 = -6

Also

(8+y_2)/2=2

8+y_2=4

y_2=4-8=-4

y_2 = -4

The coordinates of the other endpoint is (-6,-4)

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Step-by-step explanation:

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3 years ago
Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.
aleksley [76]

Given:

The expression is:

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

To find:

The value of the given expression when x=64 and y=27.

Solution:

We have,

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

Putting x=64 and y=27, we get

=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}

It can be written as

=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}

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=5-16

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Therefore, the value of the given expression -11 when x=64 and y=27.

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