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Vera_Pavlovna [14]
3 years ago
15

Help plz question is in the photo

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

A. Trinomial

Step-by-step explanation:

It says it's a polynomial and that based on the number of terms. So right then you can cancel out cubic and quadratic because they aren't polynomials. Also:

Cubic is just a variable with the exponent of 3. Examples:

x^3,y^3,z^3

Binomial is a polynomial with 2 terms. Examples:

5x+3; 6x+2; x+7

A quadratic has a division sign.

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butalik [34]

Answer:

67

4*4*4=64

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67

8 0
2 years ago
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Solve the formula for C thx if u answer!!!
kati45 [8]

Answer: The answer is C = -P + R

3 0
1 year ago
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If M = 5x2 + 7x - 4 and N = -3x2 - 4x + 5, then M - N equals
Alinara [238K]

Answer

8x^2+11x-9

Step-by-step explanation:

That is the answer :))

4 0
3 years ago
The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
andrezito [222]

Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

Simplify:

x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

then;

\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

or

\sqrt{100- 12c} = 14

Squaring both sides we get;

100-12c = 196

Subtract 100 from both sides, we get

100-12c -100= 196-100

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve x_1 , x_2

x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

or

x_1 = \frac{-10 + \sqrt{100- 96}}{6} or

x_1 = \frac{-10 + \sqrt{4}}{6}

Simplify:

x_1 = \frac{-4}{3}

Now, to solve for x_2 ;

x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}

or

x_2 = \frac{-10 - \sqrt{100- 96}}{6} or

x_2 = \frac{-10 - \sqrt{4}}{6}

Simplify:

x_2 = -2

therefore, the solution for the given equation is: -\frac{4}{3} and -2.


3 0
3 years ago
Help me please !! Tell me the algebraic expression to 1 please !!!
Anuta_ua [19.1K]
You need to distribute the 4 to both the n and the positive 5 so you’re answer would be 4n + 20.
5 0
3 years ago
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