A. P(492 < x-bar < 512)
<span>z = (492-502)/100/√90 </span>
<span>z = -0.95 is 0.1711 </span>
<span>z = (512-502)/100/√90 </span>
<span>z = 0.95 is 0.8289 </span>
<span>b. P(505 < x-bar < 525) </span>
<span>z = (505-515)/100/ √90 </span>
<span>z = -0.95 </span>
<span>z = (525-515)/100/ √90 </span>
<span>z = 0.95 </span>
<span>P(-0.95< z < 0.95) = 0.6578 </span>
<span>P(-0.95< z < 0.95) = 0.6578 </span>
<span>c. P(484 < x-bar < 504) </span>
<span>z = (484-494)/100/√100 </span>
<span>z = -1 is 0.1587 </span>
<span>z = (504-494)/100/√100 </span>
<span>z = 1 is 0.8413 </span>
<span>P(-1< z <1) = 0.6826</span>
Answer:

Step-by-step explanation:

Answer:
16
Step-by-step explanation:
Since DF and BC are similar, their ratios are:
12:3
4:1
Since AB is similar to ED:
Substituting the ratio:
x:4
Hence, x = 16
Hence, AB = 16
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Distance Firework B would have traveled after 0.25 seconds:
240 x 0.25 = 60 feet
Let x be the time that it will explode together:
60 + 240x = 340x
100x = 60
x = 60 ÷ 100
x = 0.6 sec
Firework A will explode at 0.6 seconds after it is launched
Firework B will explode at (0.6 + 0.25) 0.85 seconds after it is launched.
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Answer: Firework B will explode at 0.85 seconds after it is launched.
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