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Mamont248 [21]
3 years ago
15

Help please, I'm stuck on this :/

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Do you have a calculator? you can solve it by substituting x.

y=16x^2

0: y = 16(0)^2 = 16(0) = 0

(x = 0 , y = 0)

0.5: y = 16(0.5)^2 = 16(0.25) = 4

(x = 0.5 , y = 4)

1: y = 16(1)^2 = 16(1) = 16

(x = 1 , y = 16)

1.5: y = 16(1.5)^2 = 16(2.25) = 36

(x = 1.5 , y = 36)

2: y = 16(2)^2 = 16(4) = 64

(x = 2 , y = 64)

2.5: y = 16(2.5)^2 = 16(6.25) = 100

(x = 2.5 , y = 100)

3 : y = 16(3)^2 = 16(9) = 144

(x = 3 , y = 144)

4: y = 16(4)^2 = 16(16) = 256

(x = 4 , y = 256)

if you multiply a negative number by itself, it will become positive. So, -4, -3, -2.5, -2, -1.5, -1, -0.5 will be the same as the positive 4, 3, 2.5, 2, 1.5, 1, 0.5.

I'm not sure about the pattern, but if you graph it, it'll be symmetrical across the y-axis.

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Answer:

Step-by-step explanation:

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From trigonometry, 2sinAcosA = Sin2A

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\frac{4(sin(420-140)) }{sin280}

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3 years ago
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Answer:

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