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Butoxors [25]
3 years ago
13

A scientist needs to print a research report on her computer’s printer. If she prints in black ink only, b(t)=152-33t describes

the number of pages left to print after t minutes. If she prints in colored ink, c(t)=152-30t describes the number of pages left to print after t minutes. Based on this information, which statement is true?
F. The printer prints 3 more pages per minute in colored ink than in black ink.
G. The printer prints 3 fewer pages per minute in colored ink than in black ink.
H. The printer prints the same number of pages per minute in either type of ink.
J. The printer prints the entire research report in 152 minutes.
Mathematics
1 answer:
Flauer [41]3 years ago
3 0
With black ink      ⇒⇒⇒ <span>b(t)=152-33t
With </span>colored ink   ⇒⇒⇒ <span>c(t)=152-30t

After 1 minute :
b = 152 - 33 * 1 = 152 - 33 = 119
c = 152 - 30 * 1 = 152 - 30 = 122
c - b = 122 - 119 = 3

The correct choice is:
</span><span>G. The printer prints 3 fewer pages per minute in black ink than in colored ink.</span>
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max2010maxim [7]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

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<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

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Given angles

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  • (4x-34)°

According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

8 0
3 years ago
TIME REMAINING
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Answer:

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Answer:

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we can look at this problem using rates:

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