Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
Answer:
Step-by-step explanation:
First you need to write it down. Now, 1st step of the math, how many times will 7 go into 4? 0 times. So you have to do how many times 7 goes to 44. It goes in 6 times bc 7 times 7 is 49. Now, subtract 42 form 44 which is 2. Bring down the 2, you get 22. 7 goes into 22 3 times, subtract 21 from 22. One. So your answer is 63 remainder one!
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Answer:
is not
Step-by-step explanation:
