Answer:
Below
Step-by-step explanation:
First I found the area of the portion that extends off (if that makes sense??)
It is a triangle, so use A = bh/2
A = (2)(6) / 2
= 6 cm^2
Next I found the area of the rectangle using A = LW
A = (6)(3)
= 18 cm^2
Total area = 18 + 6
= 24 cm^2
Hope this helps! Best of luck <3
![\bold{ANSWER:}](https://tex.z-dn.net/?f=%5Cbold%7BANSWER%3A%7D)
a = 17.9 meters^2
![\bold{EXPLANATIONS:}](https://tex.z-dn.net/?f=%5Cbold%7BEXPLANATIONS%3A%7D)
Given that:
• circumference of circle = 15 meters
T= 3.14
As we know that:
• circumference of circle = 2 nr
By putting values:
•15 = 2 (3.14) r
By simplifying:
• 15=6.28r
Dividing both sides by 6.28 we get:
• r= 2.39 meters
Now for finding area:
• Area = 1 r2
Putting values:
• Area = (3.14) (2.39)*2
By simplifying we get:
• Area = 17 .935 meters’2
So by rounding off radius to nearest tenth:
• radius =r=2.4 meters
Rounding off area to nearest tenth:
• area =a = 17.9 meters’2
Vertical angles are equivalent so
7x-4=87
and 4 to both sides to remove the negative numbers, the new equation is
7x=91
Then divide both sides by 7 and you get the answer
1x=13
Makes sense?
![A=P(1+ \frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D%20)
A=end amount
P=present amount
r=rate in decimal
n=number of times per yaer compounded
t=time in years
given
P=1000
r=0.08
n=1
t=35
![A=1000(1+ \frac{0.08}{1})^{(1)(35)}](https://tex.z-dn.net/?f=A%3D1000%281%2B%20%5Cfrac%7B0.08%7D%7B1%7D%29%5E%7B%281%29%2835%29%7D%20)
![A=1000(1+ 0.08)^{35}](https://tex.z-dn.net/?f=A%3D1000%281%2B%200.08%29%5E%7B35%7D%20)
![A=1000(1.08)^{35}](https://tex.z-dn.net/?f=A%3D1000%281.08%29%5E%7B35%7D%20)
A=14785.344
roud
about $14785.34