9 chairs;
there would have to be nine chairs at a table for it to have the most chairs because in this case, even if the remaining 7 chairs were all located at one of the other tables, then the table with the 9 chairs would still have the most chairs.
Answer:
answer is 9.
Step-by-step explanation:
a+2 ,a+4 ,a+6 and a is an odd number. Now that the given is sum of the sequence is 40. So, a+a+2+a+4+a+6 = 40 Therefore 4a+12 =40 , 4a =28 , a = 7 now the question is second term so it is a+2 =9 answer is 9
If I’m not mistaken, the answer is C.