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mr_godi [17]
2 years ago
11

Given a+b=7 and a-b=3, find the following 3^a÷3^b

Mathematics
1 answer:
gulaghasi [49]2 years ago
3 0

Answer:

27

Step-by-step explanation:

a + b = 7

a - b = 3

2a = 10

a = 5

b = 7 - 5

b = 2

3⁵ / 3² = 3³ using law of indices

3³ = 27.

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2 + 7c - 4c2 – 3c + 4
iragen [17]

Answer:

-4c² + 4c +6

Step-by-step explanation:

combine like terms

2+ 4 = 6

7c - 3c = 4c

- 4c

Hope this helps!

8 0
3 years ago
Read 2 more answers
Using principle of mathematical induction prove that 6^-1 divisble by 5 .​
salantis [7]

I suppose the claim is 5 \mid 6^n - 1 for n\in\Bbb N.

When n=1, we have 6^1 - 1 = 6 - 1 = 5, and of course 5 divides 5.

Assume the claim holds for n=k, that 5 \mid 6^k - 1. We want to use this to show it holds for n=k+1, that 5 \mid 6^{k+1} - 1.

We have

6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5

Since 5 \mid 6^k - 1, we can write 6^k - 1 = 5\ell for some integer \ell. Then

6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)

which is clearly divisible by 5. QED

5 0
1 year ago
What goes in the boxes ig?
lana [24]

To convert 1.07 to a fraction, multiply it by 100.

1.07 * 100 = 107

So the percent equivalent of 1.07 is 107%.

Just put 1.07 over 100 to turn it into a fraction.

107/100 would be the fraction equivalent.

7 0
2 years ago
The photo printed has length of 6 imams width of 4. A smaller picture is printed the ratio of the new picture to the size of the
Serggg [28]
We know the width of the first picture, is 4
we know the ratio from smaller to larger is 1.5:2

thus     \bf \cfrac{\textit{width of small}}{\textit{width of large}}\qquad 1.5:2\implies \cfrac{1.5}{2}=\cfrac{w}{4}

solve for "w".

we know the length of the first picture, 6

\bf \cfrac{\textit{length of small}}{\textit{length of large}}\qquad 1.5:2\implies \cfrac{1.5}{2}=\cfrac{L}{6}


solve for "L".
3 0
3 years ago
If y+(x^2+x+1)(x^3-x-1), then y’(2)=
umka2103 [35]
Easy it’s y=learn it your self and pay attention you bum
3 0
3 years ago
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