3 years ago

How do I solve (-9,17); slope -4/3

2 answers:

8 0

You can make a graph going from -20,20 and -20,20
then after that you would want to go down 4 over 3 to the right continuously, then head in the opposite direction up 4 over 3 to the left. Once you find your y-intercept you can form your equation.
It should me y= -3/4x +41/4

tia_tia [17]3 years ago

3 0

Easy you plug in 17 in for y and -9 in for x and then -4/3 for the m to the slope intercept form which is y=mx+b and figure out what B is so it would be 17=-4/3(-9)+b and solve it

You might be interested in

Set up the integral that uses the method of disks/washers to find the volume V of the solid obtained by rotating the region boun

Blababa [14]

Answer:

$a)\: \frac{3}{2} \pi$

$b) \:\frac{47}{5} \pi$

Step-by-step explanation:

$y=3\sqrt x,\:\:y=3,\:\:x=0$

a) about the line y = 3

$3\sqrt x=3$ ⇒ $x = 1$ is the intersection point

So,

$V=\int\limits^1_0\pi(3-3\sqrt x)^2\:dx=\pi\int\limits^1_0(9-18\sqrt x+9x)\:dx=\\\\=\pi(9x-12x^{3/2}+9/2x^2)|^1_0=\pi(9-12+9/2)=\frac{3}{2} \pi$

b) about the line x = 5

$y=3\sqrt x$ ⇒ $x=y^2/9$

So,

$V = \int\limits^3_0\pi([5-0]^2-[5-y^2/9]^2)\:dy=\pi\int\limits^3_0(25-25+10y^2/9-y^4/81)\:dy=\\\\=\pi(10y^3/27-y^5/405)|^3_0=\pi(10-3/5)=\frac{47}{5} \pi$