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ella [17]
3 years ago
14

How do I solve (-9,17); slope -4/3

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0
You can make a graph going from -20,20 and -20,20
then after that you would want to go down 4 over 3 to the right continuously, then head in the opposite direction up 4 over 3 to the left. Once you find your y-intercept you can form your equation.  
It should me y= -3/4x +41/4
tia_tia [17]3 years ago
3 0
Easy you plug in 17 in for y and -9 in for x and then -4/3 for the m to the slope intercept form which is y=mx+b and figure out what B is so it would be 17=-4/3(-9)+b and solve it
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23% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and as
zlopas [31]

Answer:

a) There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

b) There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

c) There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this exercise using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 students are randomly selected, so n = 10.

23% of college students say they use credit cards because of the rewards program. This means that \pi = 0.23

(a) exactly two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities of these events must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733

P(X = 1) = C_{10,1}.(0.23)^{1}.(0.77)^{9} = 0.2188

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0733 + 0.2188 + 0.2942 = 0.5863

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.5863 = 0.4137

There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

(c) between two and five inclusive.

This is

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343

P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225

P(X = 5) = C_{10,3}.(0.23)^{5}.(0.77)^{5} = 0.0439

So

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.2942 + 0.2343 + 0.1225 + 0.0439 = 0.6949

There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

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Anastaziya [24]

I hope I have helped you

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Answer:

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Step-by-step explanation:

To solve first you need to isolate the absolute value sign. Do this by subtracting 7 from each side.

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