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2 years ago

Why is 100 even number

1 answer:

4 0

Because it is divisible by other numbers besides 1 and itself. See, a primary number is a number that can only be divided equally by 1 and itself. 100 can be divided by 2, 4, 5, 20, 25, 50. Numbers that aren't 1 or 100.

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Tammy Ray purchases 20 file cabinets for $986.99. What is<br> the price per cabinet?

RSB [31]

Answer:

Step-by-step explanation:

986.99/20=49.3485

Divide 986.99 by 20 which gets you 49.3485 then just around up the 10.

Hope this helps! Have a great day. Remember your amazing and you got this! Alycia <3

7 0

2 years ago

Read 2 more answers

Cady found that she uses half of a roll of paper towels each week. How many rolls of paper towels will she use in 12 weeks?

Lady_Fox [76]

Answer:

6 paper towel rolls

Step-by-step explanation:

If she uses 1/2 of a paper towel roll each week and there are twelve weeks, divide the number of weeks by the number of paper towel rolls she uses.

3 0

2 years ago

If the probability of an events is 2/7 what must be the probability of its compliments

monitta

Answer:

The probability of its compliments = 0.7143 = 5/7

Step-by-step explanation:

The probability of an events = P= 2/7 = 0.2857

The probability of its compliments = 1-p = 1-0.2857 = 0.7143 = 5/7

6 0

3 years ago

What is value of x and y if<br> Y=-2x+8 and Y=3x-7

iren [92.7K]

Answer:

X=5 y=-2

Step-by-step explanation:

Set them equal to each other so...

-2x+8=3x-7

Simplify by balancing out the equation so

-5x=-1

So x=5

Now plug it into either y equation

-2(5)+8

-10+8

Y=-2

Hope this helps!

3 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

2 years ago