Answer:
If
or
, there is only one solution to the given quadratic equation.
Step-by-step explanation:
Given a second order polynomial expressed by the following equation:
![ax^{2} + bx + c, a\neq0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%2B%20bx%20%2B%20c%2C%20a%5Cneq0)
This polynomial has roots
such that
, given by the following formulas:
![x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%20%5Cfrac%7B-b%20%2B%20%5Csqrt%7B%5Cbigtriangleup%7D%7D%7B2%2Aa%7D)
![x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%20%5Cfrac%7B-b%20-%20%5Csqrt%7B%5Cbigtriangleup%7D%7D%7B2%2Aa%7D)
![\bigtriangleup = b^{2} - 4ac](https://tex.z-dn.net/?f=%5Cbigtriangleup%20%3D%20b%5E%7B2%7D%20-%204ac)
The signal of
determines how many real roots an equation has:
: Two real and different solutions
: One real solution
: No real solutions
In this problem, we have the following second order polynomial:
.
This means that ![a = k+1; b = 4k; c = 2](https://tex.z-dn.net/?f=a%20%3D%20k%2B1%3B%20b%20%3D%204k%3B%20c%20%3D%202)
It has one solution if
![\bigtriangleup = 0](https://tex.z-dn.net/?f=%5Cbigtriangleup%20%3D%200)
![b^{2} - 4ac = 0](https://tex.z-dn.net/?f=b%5E%7B2%7D%20-%204ac%20%3D%200)
![16k^{2} -8(k+1) = 0](https://tex.z-dn.net/?f=16k%5E%7B2%7D%20-8%28k%2B1%29%20%3D%200)
![16k^{2} - 8k - 8 = 0](https://tex.z-dn.net/?f=16k%5E%7B2%7D%20-%208k%20-%208%20%3D%200)
We can simplify by 8
![2k^{2} - k - 1 = 0](https://tex.z-dn.net/?f=2k%5E%7B2%7D%20-%20k%20-%201%20%3D%200)
The solution is:
or ![k = -\frac{1}{2}](https://tex.z-dn.net/?f=k%20%3D%20-%5Cfrac%7B1%7D%7B2%7D)
So, if
or
, there is only one solution to the given quadratic equation.
About 12.56 units.
Solve for x by plugging in values into Pythagorean theorem.
![a^{2} +b^{2} = c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3D%20c%5E%7B2%7D%20)
![x^{2} +(x+12)^{2} = 34^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%28x%2B12%29%5E%7B2%7D%20%3D%2034%5E%7B2%7D%20)
Simplify
![2x^{2} + 24x+144 = 1156](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B%2024x%2B144%20%3D%201156%20)
Subtract 144 from both sides
![2x^{2} + 24x = 1012](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B%2024x%20%3D%201012)
divide both sides by 2
![x^{2} + 12x = 506](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%2012x%20%3D%20506)
complete the square
![x^{2} + 12x + 36 = 506 +36 . = (x+6)^2 = 542](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%2012x%20%2B%2036%20%3D%20506%20%2B36%20.%20%3D%20%28x%2B6%29%5E2%20%3D%20542)
take the square root of both sides.
![x+6 = 23.28](https://tex.z-dn.net/?f=x%2B6%20%3D%2023.28)
subtract by 6 to get about 17.28 for x.
Plug in values for x to get distance traveled on outside of the yard.
17.28 + (17.28 +12) = 46.56
subtract 34 from the length to get the difference in travel. 46.56-34=12.56
Answer:
c
Step-by-step explanation:
hope this helps
I believe the answer is 2, the 3 large circles are filled with 5 dots each, the total number of dots is 17. 15 is the number closest to 17 that can be divided by 3 therefore there would be 2 left over (the 2 dots on the outside)