Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
-1
Step-by-step explanation:
Took the assignment! :)
Answer:
click the button and use it as and use it
Answer:
C
Step-by-step explanation:
in trangle NET the angles are 81 and 34 so the other angle must be 180-81-34=65, the other triangle has the same measurments for angles 81-34-65 so the triangles are similar because of AA similarity theorem
ΔHMJ~ΔNET by AA similarity
