5u > 64 - 14
5u > 50
u > 10
You end up at the point (5, 5).
1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
Answer:
The formula for calculating the percent change in a value between two points in time is:
p
=
N
−
O
O
⋅
100
Where:
p
is the percent change - what we are solving for in this problem.
N
is the New Value - 5 in this problem.
O
is the Old Value - 4 in this problem.
Substituting and solving for
p
gives:
p
=
5
−
4
4
⋅
100
p
=
1
4
⋅
100
p
=
100
4
p
=
25
There was a 25% increase from 4 to 5.
Step-by-step explanation:
Answer:
5/3
Step-by-step explanation:
Tangent is defined as the length of the opposite side of the triangle divided by the length of the adjacent side of the triangle. Since you know that two of the legs are 3 and 4, using the pythagorean theorem you know that the last side is 5. Sin is defined as the length of the opposite side divided by the length of the hypotenuse, which in this case is 3/5. Cosecant is just the reciprocal of that, or 5/3. Hope this helps!
