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Andrew [12]
2 years ago
6

Molly is painting a model house and needs to know how much paint she will need. She knows the surface area of the prism is 216 s

quare inches and the surface area of the pyramid is 84 square inches.
1. Which surface is shared by the two solids? What are the dimensions of this surface?

2. There is another surface that Molly does not need to paint, because it won’t show when she displays the model house. Describe that surface, and explain why it doesn't need to be painted.

3. To find the area Molly needs to paint, she should add the surface areas of both solids and subtract:

twice the area of the triangle
twice the area of the square
three times the area of the square
the area of the square

4. Find the area Molly needs to paint. Show your work, and be sure to include units with your answer.

Oh and here's an image to help you out

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
5 0

Answer:

1. Base of pyramid; 6 in by 6 in

2. Base of prism; Its dimensions are also 6 in by 6 in, located at the bottom of the house and will not be seen, so it does not require painting.

3. twice the area of the square

4. Area = 228 inches squared

Step-by-step explanation:

For question 4, the area Molly needs to paint is found by adding all the surface areas and subtracting the 2 surfaces that will not be painted: base of pyramid and base of prism (outlined in red). According to the picture, these are both squares with 6 by 6 dimensions.

<h3>Step 1. Add all surface areas together</h3>

Prism: 6 surfaces

Surface area = 216 inches sq

  • Front = 6 x 6 = 36
  • Back = 6 x 6 = 36
  • Top = 6 x 6 = 36
  • Bottom (base) = 6 x 6 = 36
  • Side = 6 x 6 = 36
  • Other side = 6 x 6 = 36

Pyramid: 5 surfaces

Surface area = 84 inches sq

  • Bottom (base) = 6 x 6 = 36
  • Front triangle = (6 x 4)/2 = 12
  • Back = (6 x 4)/2 = 12
  • Side = (6 x 4)/2 = 12
  • Other side = (6 x 4)/2 = 12

TOTAL surface area: 216 inches + 84 inches = 300 inches sq

<h3>Step 2. Subtract surfaces that are NOT being painted</h3>

300 - base of pyramid - base of prism

300 - 2(36)

300 - 72

<u>228 inches sq</u>

Hope this helps!

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Answer:

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1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

ln e^{-0.2n} = ln (\frac{8}{75})

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lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

P(n) = \frac{0.83}{1+e^{-0.2t}}

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

So the number of correct reponses  after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

0.75 =\frac{0.83}{1+e^{-0.2n}}

And we can rewrite this expression like this:

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

Now we can apply natural log on both sides and we got:

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

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