(2x - 5)° + 45° = 180°
2x° + (-5 + 45)° = 180°
2x° + 40° = 180°
2x° = 180° - 40°
2x° = 140°
x° = 140 ÷ 2
x° = <u>7</u><u>0</u><u>°</u>
So, the value of x is 70°
<em>Hope it helps and is useful</em><em> </em><em>:</em><em>)</em>
Answer:
I'm pretty sure that the answer is 5. Correct me if i'm wrong
Step-by-step explanation:
Isolate the x in both cases. What you do to one side, you do to the other.
11x + 4 < 15
Subtract 4 from both sides
11x + 4 (-4) < 15 (-4)
11x < 11
isolate the x, divide 11 from both sides
11x/11 < 11/11
x< 1
x < 1 is your answer for the first one
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Again, isolate the x.
12x - 7 > -25
Add 7 to both sides
12x - 7 (+7) > -25 (+7)
12x > -18
Isolate the x, divide 12 from both sides
12x/12 > -18/12
x > -1.5 is your answer for the second one.
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hope this helps
Answer:
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
Step-by-step explanation:
Given:
Number is
200.06
For option A)
2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
= 200 + 0 + 0 + 0.06
= 200.06
Which is CORRECT.
For option B)
2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000
= 200 + 0 + 0 + 0.006
=200.006
Which is INCORRECT.
For option C)
2 × 100 + 6 × 1/10
= 200 + 0.6
= 200.6
Which is INCORRECT.
For option D)
2 × 100 + 6 × 1/100
= 200 + 0.06
= 200.06
Which is CORRECT.
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots
