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umka21 [38]
2 years ago
8

The base of a solid S is the region bounded by the parabola x^2=8y

Mathematics
1 answer:
nexus9112 [7]2 years ago
8 0

Step-by-step explanation:Updated answer is the second one

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Is the confidence interval affected by the fact that the data appear to be from a population that is not normally​ distributed?
sp2606 [1]

Answer:

D. No, because the sample size is large enough.

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

If the sample size is higher than 30, on this case the answer would be:

D. No, because the sample size is large enough.

And the reason is given by The Central Limit Theorem since states if the individual distribution is normal then the sampling distribution for the sample mean is also normal.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

If the sample size it's not large enough n<30, on that case the distribution would be not normal.

7 0
3 years ago
What is the value of h when the function is converted to vertex form?
Dmitrij [34]

Answer:  The value of 'h' is 3.

Step-by-step explanation:  Given that the vertex form of a function is given by

g(x)=a(x-h)^2+k~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the value of 'h' when the following function is converted to the vertex form.

g(x)=x^2-6x+14~~~~~~~~~~~~~~~~~~~~~~(ii)

From equation (ii), we have

g(x)=x^2-6x+14\\\\\Rightarrow g(x)=x^2-2\times x\times 3+3^2-3^2+14\\\\\Rightarrow g(x)=(x-3)^2-9+14\\\\\Rightarrow G(x)=(x-3)^2+5.

Comparing it with the vertex form (i), we get

h=3.

Thus, the value of 'h' is 3.

4 0
3 years ago
What are the solutions to the quadratic equation x2 – 16 = 0?
nika2105 [10]
Can you be more specific?
4 0
2 years ago
1. y = x2 + 2x – 8<br><br> Axis of Symmetry:<br><br> Vertex:<br><br> Domain:<br><br> Range:
valentinak56 [21]

Answer:

Axis of Symmetry: x=-1

Vertex: (-1,-9)

Domain:   (- ∞ ,∞ )

Range: (-9,∞ )

Step-by-step explanation:

6 0
3 years ago
Whats the table function for y=2x-5
algol13

y = 2x - 5

<u>    x     |     y     </u>

<u>   -1     | 2(-1) - 5 = -7</u>

<u>    0    |  2(0) - 5 = -5</u>

<u>     1    |  2(1) - 5 = -3</u>

<u>    2    |  2(2) - 5 = -1</u>

<u>    3    |   2(3) - 5 = 1</u>

etc.

3 0
3 years ago
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