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3 years ago

13

Work out the area of this shape. ? cm2 4 cm 9 cm 6 cm 12 cm Help!!!

1 answer:

mars1129 [50]3 years ago

7 0

Answer:

84 cm^2

Step-by-step explanation:

Area of triangle + area of rectangle

Area of triangle = 1/2*l*b

= 1/2*8*3= 12 cm^2

Area of rectangle = l*b

= 12*6 = 72 cm^2

Total area= 72+12

= 84 cm^2

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Nataly_w [17]

Answer:

The equation that models the situation is $s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}$ .

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

$v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o})$ (1)

Where:

$s_{o}$ , $s_{f}$ - Initial and final position of the softball, measured in feet.

$a$ - Acceleration, measured in meters per square second.

$v_{o}$ , $v_{f}$ - Initial and final velocities of the softball, measured in feet per second.

If we know that $v_{o} = 50\,\frac{ft}{s}$ , $a = -32.174\,\frac{m}{s^{2}}$ and $s_{o} = 4\,ft$ , then the equation that models the situation is:

$v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)$

Then, we clear the final position of the softball:

$-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4$

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The equation that models the situation is $s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}$ .

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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3 years ago

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Tema [17]

Answer:

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Step-by-step explanation:

This may look like a complicated problem but it's some simple analyzing of the problem to get the job done:

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Therefore, we need to add 2 groups:

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